HDU 1003 Max Sum(动态规划)

                             Max Sum

                              Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

                                                 Total Submission(s): 107407    Accepted Submission(s): 24742

Problem Description

Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.

 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).

 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.

 

Sample Input

2

5 6 -1 5 4 -7

7 0 6 -1 1 -6 7 -5

 

Sample Output

Case 1:

14 1 4

 

Case 2:

7 1 6

 

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1003

 

#include <stdio.h>

int main()
{
    int T, N;
    scanf("%d", &T);
    for(int i = 1; i <= T; i++)
    {
        int sum = 0, k = 1, nTemp;
        int max_sum = -0x7ffffff;
        int sSeq, eSeq;

        scanf("%d", &N);
        for(int j = 1; j <= N; j++)
        {
            scanf("%d", &nTemp);
            sum += nTemp;
            if(sum > max_sum)
            {
                max_sum = sum;
                sSeq = k;
                eSeq = j;
            }
            if(sum < 0)        //如果总和小于0，则其实位置从下一个开始
            {
                k = j + 1;
                sum = 0;
            }
        }
        if(i != 1)
            printf("\n");
        printf("Case %d:\n", i);
        printf("%d %d %d\n", max_sum, sSeq, eSeq);
    }
    return 0;
}

 总结：发现自己题目做的太少了，以至于连很简单的题目都做不出来，只能说自己还不够努力吧！