摘要: 题目:Atcoder E - Integer Sequence Fair E - Integer Sequence Fair (atcoder.jp) 题意: 反正其实就是求m的(k的n次方) 思路: 求m的(k的n次方)的次方,mod为998244353; 1.如果m是mod倍数直接输出0, 2. 阅读全文
posted @ 2021-11-20 22:05 Curry_BP 阅读(100) 评论(0) 推荐(0)