摘要: 1 #include <stdio.h> 2 int main() 3 { 4 int n; 5 scanf("%d", &n); 6 for (int i = 1; i <= n / 2 + 1; i++) 7 { 8 for (int j = 0; j < 2 * (n / 2 - i + 1) 阅读全文
posted @ 2021-10-29 21:29 Colin_Cora 阅读(165) 评论(0) 推荐(0)