======================= **基础知识** =======================

哈希表:为了解决快速索引树问题的结构

  数组中根据下标可以O(1) 实现数据获取; 但是在实际应用中,可能要根据复杂的数据结构来查找数据;

  所以要实现将任意数据 到 数组下标的映射就可以实现任意类型数据之间的关联,实现O(1) 查找;

  哈希函数: 任意数据 到 数组下标的映射; 体现设计能力(数学能力),有很多论文!

  哈希操作: 高维空间 到 低维空间 的映射;当多个 高维空间数据 映射到 同一个低维空间时候,就产生了哈希冲突

   哈希冲突: 无法避免,高维 到 低维 压缩过程中 必然会产生重叠;重点是解决冲突;

  冲突处理:有下面4个处理方法, 各个方法要看具体设计方法,不是一层不变的;

      开放定址法: 在已经算出的下标,再计算得到下一个下标;例如线性探测法:在冲突下标 + 1;

                    二次再散射: 第一次冲突 + 12, 第二次冲突+ 22,三次:32  ... 

      注意点: //对于这种方法,在反复插入,删除操作中,如何保证查找过程一定能找到最后一位,也很重要;例如插入多次后,某个位置发生多次冲突,然后删除中间的值,对于后面的值查找如何保证一定能找到冲突后面的所有情况,也要考虑;

    706. 设计哈希映射 :开放定址法 VS 拉链法;这里开放定址法对于冲突处理并不完善,只好通过增加数据size 解决;

  1 //开放定址法:
  2 class MyHashMap {
  3 public:
  4 #define MULP 3 
  5 #define MAX_NUM 100000  //为了通过,减少因为冲突处理,导致的不断更新下标,然后删除中间冲突值,造成后面值查找出错;
  6                         //或者考虑更新冲突处理方法
  7     typedef pair<int, int> PII;
  8     vector<PII*> arr;
  9     int cnt;
 10     MyHashMap(int c = MAX_NUM): cnt(0), arr(c, nullptr){}
 11 
 12     int hashFunc(int key, int value) {
 13         int t = 1;
 14         int index = key % arr.size();
 15 
 16         while(arr[index] && arr[index]->first != key) {
 17             index = (index + (t * t)) % arr.size();
 18             t += 1;
 19 
 20             if(t > 50) {
 21                 expand();
 22                 t = 1;
 23                 index = key % arr.size();
 24             }
 25         }
 26 
 27         return index;
 28     }
 29 
 30     void expand() {
 31         MyHashMap mh(cnt * MULP);
 32         for(auto &x : arr) {
 33             if(!x) continue;
 34             mh.put(x->first, x->second);
 35             delete x;
 36             x = nullptr;
 37         }
 38         *this = mh;
 39         return;
 40     }
 41     
 42     void put(int key, int value) {
 43         int index = hashFunc(key, value);
 44 
 45         if(!arr[index]) {
 46             arr[index] = new PII(make_pair(key, value));
 47             cnt += 1;
 48         } else arr[index]->second = value;
 49 
 50         if(cnt * MULP > arr.size()) expand();
 51         return;
 52     }
 53 
 54     int get(int key) {
 55         int index = hashFunc(key, 0);
 56         if(arr[index]) return arr[index]->second;
 57 
 58         return -1;
 59     }
 60     
 61     void remove(int key) {
 62         int index = hashFunc(key, 0);
 63 
 64         if(arr[index]) {
 65             delete arr[index];
 66             arr[index] = nullptr;
 67             cnt -= 1;
 68         }
 69         return;
 70     }
 71 };
 72 
 73 /**
 74  * Your MyHashMap object will be instantiated and called as such:
 75  * MyHashMap* obj = new MyHashMap();
 76  * obj->put(key,value);
 77  * int param_2 = obj->get(key);
 78  * obj->remove(key);
 79  */
 80 
 81 //original
 82 
 83 //拉链法: 
 84 struct Node{
 85     int key, val;
 86     Node *next;
 87 
 88     Node(int k = -1, int v = -1): key(k), val(v), next(nullptr) {}
 89 
 90     void insert_after(Node* np) {
 91         np->next = next;
 92         next = np;
 93         return;
 94     }
 95 
 96     void remove_next(Node* pp) {
 97         Node *rp  = pp->next; 
 98         if(!rp) return ;
 99         pp->next = rp->next;
100         delete rp;
101         return;
102     }
103 
104 };
105 class MyHashMap {
106     private:
107         int hash_table(int key) { return key & 0x7FFFFFFF;}
108         int cnt ;
109         vector<Node> arr;
110     public:
111         /** Initialize your data structure here. */
112         MyHashMap(int n = 10): cnt(0), arr(n,Node()) {}
113 
114         /** value will always be non-negative. */
115         void put(int key, int value) {
116             int ind =  hash_table(key) % arr.size();
117             Node *now = &arr[ind];
118             while(now->next && now->next->key != key) now = now->next;
119             if(now->next) {
120                 now->next->val = value;
121                 return;
122             }
123             Node *np = new Node{key, value};
124             now->insert_after(np);
125             return;
126         }
127 
128         /** Returns the value to which the specified key is mapped, or -1 if this map contains no mapping for the key */
129         int get(int key) {
130             int ind = hash_table(key) % arr.size();
131             Node *now = &arr[ind];
132             while(now->next && now->next->key != key) now = now->next;
133             if(now->next == nullptr) return -1;
134             else return now->next->val;
135         }
136 
137         /** Removes the mapping of the specified value key if this map contains a mapping for the key */
138         void remove(int key) {
139             int ind = hash_table(key) % arr.size();
140             Node *now = &arr[ind];
141             while(now->next && now->next->key != key) now = now->next;
142             if(now->next) now->remove_next(now);
143             return;
144         }
145 };
146 
147 /**
148  * Your MyHashMap object will be instantiated and called as such:
149  * MyHashMap* obj = new MyHashMap();
150  * obj->put(key,value);
151  * int param_2 = obj->get(key);
152  * obj->remove(key);
153  */
开放定址法/拉链法

      建立公共溢出区: 将所有的冲突的值都放在一个公共的溢出缓冲区(这个缓冲区可以用其他数据结构维护,例如RB tree) ; 必须借助其他数据结构实现;

      链式地址法(拉链法): 将冲突值通过链表方式实现共存,每个区间对应的是一个链表头节点;这种方法最为推荐

      再hash 法: 设计多个哈希函数,多到保证不冲突;实际应用中很难设计足够多的哈希函数;但是可以配合其他方案共同使用;

 

  装填因子: 存储元素个数 / 哈希总容量 = 0.75 , 一般操作装填因子,就要考虑扩容;要不然有些冲突处理方式在数据接近饱和时候,效率会变得极低;

 

布隆过滤器: 存储空间与元素数量无关;  能够大概率判断没有存在,但是存在一定损耗(误判率);

传统哈希表:存储空间与元素数量有关; 这也是在设计哈希表时候要合理判断数据范围,及扩容的必要性;

 布隆过滤器基本思想是: 通过多个哈希函数,然后将得到的下标映射值 分别标记在存储区; 在判断是否存在时,如果对应的所有hash 映射下标都是标记过的,大概率就是存在的;否则肯定不存在;

  这里对于哈希函数设计要求也很多;

 

 

哈希链表:哈希能够实现快速查找;链表能够实现数据自由增删改,只是查找效率O(n); 所以混合在一起实现既能快速查找;

146. LRU 缓存 :这里锻炼程序封装能力;在链表章节中, 也提到哈希链表;

  1 class LRUCache {
  2 public:
  3     struct Node{
  4         int key, val;
  5         Node *prev, *next;  //LRU 顺序
  6         Node(int k = -1, int v = -1, Node *p = nullptr, Node *n = nullptr): key(k), val(v), prev(p), next(n) {}
  7         void remove_this(){
  8             if(prev) {
  9                 prev->next = next;
 10                 next->prev = prev;
 11                 prev = nullptr;
 12                 next = nullptr;
 13             }
 14             return;
 15         }
 16         void insert_before(Node *pn) {
 17             pn->next = this;
 18             pn->prev = prev;
 19             prev->next = pn;
 20             prev = pn;
 21             return;
 22         }
 23         Node *pop_next(){
 24             Node *temp = next;
 25             next = temp->next;
 26             temp->next->prev = this;
 27             return temp;
 28         }
 29     };
 30 
 31     unordered_map<int, Node*> arr;  //借助STL中的 unordered_map
 32     int cnt, capacity;
 33     Node *head, *tail;
 34 
 35     LRUCache(int capacity): cnt(0), capacity(capacity), head(new Node()), tail(new Node()){
 36         head->prev = tail;
 37         head->next = tail;
 38         tail->prev = head;
 39         tail->next = head;
 40     }
 41 
 42     void update_seq(Node *pn){
 43         pn->remove_this();
 44         tail->insert_before(pn);
 45         if(cnt > capacity) {
 46             arr.erase(head->next->key);
 47             delete head->pop_next();
 48             cnt -= 1;
 49         }
 50         return;
 51     }
 52 
 53     int get(int key) {
 54         int ret = -1;
 55         if(arr.find(key) != arr.end()){
 56             ret = arr[key]->val;
 57             update_seq(arr[key]);
 58         }
 59         return ret;
 60     }
 61 
 62     void put(int key, int value) {
 63         if(arr.find(key) != arr.end()) {
 64             arr[key]->val = value;
 65         } else {
 66             arr[key] = new Node(key, value);
 67             cnt += 1;
 68         }
 69         update_seq(arr[key]);
 70         return;
 71     }
 72 };
 73 
 74 /**
 75  * Your LRUCache object will be instantiated and called as such:
 76  * LRUCache* obj = new LRUCache(capacity);
 77  * int param_1 = obj->get(key);
 78  * obj->put(key,value);
 79  */
 80 
 81 //哈希表,以及LRU 不断更新关系,全部自己实现;冲突处理采用拉链法,大数据时候超时,主要还是hashFunc/冲突处理都太粗糙了;
 82 //不过主要锻炼自己能力
 83 //
 84 
 85 //MY  class LRUCache {
 86 //MY     struct Node {
 87 //MY         Node(int k = -2, int v = -2): key(k), val(v),
 88 //MY         prev(nullptr), next(nullptr), Hprev(nullptr), Hnext(nullptr) {}
 89 //MY
 90 //MY         Node(int k, int v, Node* HP): key(k), val(v),
 91 //MY         prev(nullptr), next(nullptr), Hprev(HP), Hnext(nullptr) {
 92 //MY             HP->Hnext = this;
 93 //MY         }
 94 //MY         void remove_this() {
 95 //MY             prev->next = next;
 96 //MY             next->prev = prev;
 97 //MY             prev = nullptr;
 98 //MY             next = nullptr;
 99 //MY             return;
100 //MY         }
101 //MY
102 //MY         void insert_prev(Node *pn) {
103 //MY             prev->next = pn;
104 //MY             pn->prev = prev;
105 //MY             pn->next = this;
106 //MY             prev = pn;
107 //MY             return;
108 //MY         }
109 //MY
110 //MY         void pop_next() {
111 //MY             Node *rp = next;
112 //MY             rp->remove_this();
113 //MY
114 //MY             rp->Hprev->Hnext = rp->Hnext;
115 //MY             if(rp->Hnext) rp->Hnext->Hprev = rp->Hprev;
116 //MY             delete rp;
117 //MY             rp = nullptr;
118 //MY             return;
119 //MY         }
120 //MY
121 //MY         int key, val;
122 //MY         Node *prev, *next, *Hprev, *Hnext;   //H:同一组index 对应的关系;
123 //MY     };
124 //MY public:
125 //MY     int capacity, size;
126 //MY     vector<Node*> addr;
127 //MY     Node *head, *end;
128 //MY
129 //MY     int hashFunc(int key) {
130 //MY         return key;
131 //MY     }
132 //MY     LRUCache(int capacity): capacity(capacity), size(0),
133 //MY     addr(capacity, new Node()), head(new Node()), end(new Node()){
134 //MY         head->next = end;
135 //MY         head->prev = end;
136 //MY         end->prev = head;
137 //MY         end->next = head;
138 //MY     }
139 //MY
140 //MY     void update_seq(Node *temp) {
141 //MY         end->insert_prev(temp);
142 //MY         if(size > capacity){
143 //MY             head->pop_next();
144 //MY             size -= 1;
145 //MY         }
146 //MY         return;
147 //MY     }
148 //MY
149 //MY     int get(int key) {
150 //MY         int ret = -1;
151 //MY         int index = hashFunc(key) % capacity;
152 //MY         Node *temp  = addr[index];
153 //MY         while(temp->Hnext && temp->Hnext->key != key) temp = temp->Hnext;
154 //MY         if(temp->Hnext) {
155 //MY             ret = temp->Hnext->val;
156 //MY             temp->Hnext->remove_this();
157 //MY             update_seq(temp->Hnext);
158 //MY         }
159 //MY         return ret;
160 //MY     }
161 //MY
162 //MY     void put(int key, int value) {
163 //MY         int index = hashFunc(key) % capacity;
164 //MY         Node *temp = addr[index];
165 //MY         while(temp->Hnext && temp->Hnext->key != key) temp = temp->Hnext;
166 //MY         if(temp->Hnext) {
167 //MY             temp = temp->Hnext;
168 //MY             temp->val = value;
169 //MY             temp->remove_this();
170 //MY         } else {
171 //MY             temp = new Node(key, value, temp);
172 //MY             size += 1;
173 //MY         }
174 //MY         update_seq(temp);
175 //MY     }
176 //MY };
177 
178 /**
179  * Your LRUCache object will be instantiated and called as such:
180  * LRUCache* obj = new LRUCache(capacity);
181  * int param_1 = obj->get(key);
182  * obj->put(key,value);
183  */
哈希链表

======================= **代码演示** =======================

1. BKDR hash:将字符映射成整型方法; 冲突处理使用 开放定址法;

 1 #include <iostream>
 2 #include <string>
 3 #include <vector>
 4 using namespace std;
 5 
 6 class HashTable {
 7     public:
 8         HashTable(int n = 100): cnt(0) , data(n), flag(n){}
 9         void insert(string s) {
10             int ind = hash_func(s) % data.size();  //计算hash 值
11             recalc_ind(ind, s);  //冲突处理
12             if(!flag[ind]) {
13                 data[ind] = s;
14                 flag[ind] = true;
15                 cnt++;
16             }
17             //哈希扩容: 超过装填因子,就要扩容;
18             if(cnt * 100 > data.size() * 75) {
19                 expand();
20             }
21             return ;
22         }
23         bool find(string s) {
24             int ind = hash_func(s) % data.size();
25             recalc_ind(ind, s);
26             return flag[ind];
27         }
28     private:
29         int cnt;
30         vector<string> data;
31         vector<bool> flag;   //是否存储了数据: 0 : 没有; 1 : 存了;
32         int hash_func(string &s) {
33             int seed = 131, hash = 0;
34             for(int i = 0 ; s[i]; i++){
35                 hash = hash * seed + s[i];  //BKDR hash
36             }
37             return hash & 0x7FFFFFFF;
38         }
39         //开放定址法:
40         void recalc_ind(int &ind, string &s) {
41             int t = 1;  
42             while(flag[ind] && s != data[ind]) {
43                 ind += t * t;
44                 t++;
45                 ind %= data.size();
46             }
47             return;
48         }
49         void expand(){
50             int n = data.size() * 2;
51             HashTable h(n);
52             for(int i = 0; i < data.size(); i++) {
53                 if(!flag[i])  continue;
54                 h.insert(data[i]);
55             }
56             *this = h;
57             return;
58         }
59 
60 
61 };
62 
63 int main()
64 {
65     int op;
66     string s;
67     HashTable h;
68     while(cin >> op >> s) {
69         switch(op) {
70             case 1: h.insert(s); break;
71             case 2: cout << "find " << s << "in h : " << h.find(s) << endl; break;
72 
73         }
74     }
75 
76     return 0;
77 }
BKDR/开放定址法

2. 公共溢出区法:冲突解决中,不需要重新计算index, 只要把值放在公共溢出区即可;find 方法也更新了;

 1 #include <iostream>
 2 #include <string>
 3 #include <vector>
 4 #include <set>
 5 using namespace std;
 6 
 7 class HashTable {
 8     public:
 9         HashTable(int n = 100): cnt(0) , data(n), flag(n){}
10         void insert(string s) {
11             int ind = hash_func(s) % data.size();  //计算hash 值
12             recalc_ind(ind, s);  //冲突处理
13             if(!flag[ind]) {
14                 data[ind] = s;
15                 flag[ind] = true;
16             }else {
17                 buff.insert(s);
18             }
19 
20             cnt++;
21             if(cnt * 100 > data.size() * 75) {
22                 expand();
23             }
24             return ;
25         }
26         bool find(string s) {
27             int ind = hash_func(s) % data.size();
28             if(!flag[ind]) return false;
29             if(flag[ind] && data[ind] == s) return true;
30             return buff.find(s) != buff.end();
31         }
32     private:
33         int cnt;
34         vector<string> data;
35         vector<bool> flag;   //是否存储了数据: 0 : 没有; 1 : 存了;
36         set<string> buff;
37 
38         int hash_func(string &s) {
39             int seed = 131, hash = 0;
40             for(int i = 0 ; s[i]; i++){
41                 hash = hash * seed + s[i];  //BKDR hash
42             }
43             return hash & 0x7FFFFFFF;
44         }
45         //公共溢出区
46         void recalc_ind(int &ind, string &s) {
47             return;
48         }
49         void expand(){
50             int n = data.size() * 2;
51             HashTable h(n);
52             for(int i = 0; i < data.size(); i++) {
53                 if(!flag[i])  continue;
54                 h.insert(data[i]);
55             }
56             for(auto x : buff){
57                 h.insert(x);
58             }
59             *this = h;
60             return;
61         }
62 };
63 
64 int main()
65 {
66     int op;
67     string s;
68     HashTable h;
69     while(cin >> op >> s) {
70         switch(op) {
71             case 1: h.insert(s); break;
72             case 2: cout << "find " << s << "in h : " << h.find(s) << endl; break;
73 
74         }
75     }
76 
77     return 0;
78 }
公共溢出区

3.  拉链法:将所有值放在链表中存储;更新了查找方式;

 1 #include <iostream>
 2 #include <string>
 3 #include <vector>
 4 using namespace std;
 5 
 6 struct Node {
 7     string str;
 8     Node *pre, *next; //其实不用pre 也可以,当前实现中并没有用到pre
 9     Node(string s1 = "", Node* p1 = nullptr, Node* n1 = nullptr) : str(s1), pre(p1), next(n1){}
10 
11     void insert_front(string n1) {
12         Node *np = new Node(n1);
13         if(next) next->pre = np;
14         np->next = next;
15         np->pre = this;
16         next = np;
17         return;
18     }
19 };
20 class HashTable {
21     public:
22         HashTable(int n = 100): cnt(0) , data(n, new Node()){}
23         void insert(string s) {
24             int ind = hash_func(s) % data.size();  //计算hash 值
25             recalc_ind(ind, s);  //冲突处理
26 //rev1 : 没有查重
27 //rev1            data[ind]->insert_front(s);
28 //rev1            cnt++;
29 //rev1            if(cnt * 100 > data.size() * 75) {
30 //rev1                expand();
31 //rev1            }
32            Node *p = data[ind]; 
33            while(p->next && p->next->str != s) p = p->next;
34            if(nullptr == p->next) {
35                p->insert_front(s);
36                cnt++;
37                 //拉链法装填因子可以 > 1
38                if(cnt > data.size() * 3) expand();
39            }
40             return ;
41         }
42         bool find(string s) {
43             int ind = hash_func(s) % data.size();
44             Node *temp = data[ind]->next;
45             while(temp) {
46                 if(temp->str == s) return true;
47                 temp = temp->next;
48             }
49             return false;
50         }
51     private:
52         int cnt;
53         vector<Node*> data;
54         int hash_func(string &s) {
55             int seed = 131, hash = 0;
56             for(int i = 0 ; s[i]; i++){
57                 hash = hash * seed + s[i];  //BKDR hash
58             }
59             return hash & 0x7FFFFFFF;
60         }
61         //拉链法
62         void recalc_ind(int &ind, string &s) {
63             return;
64         }
65         void expand(){
66             int n = data.size() * 2;
67             HashTable h(n);
68             for(int i = 0; i < data.size(); i++) {
69                 Node *p = data[i]->next;
70                 if(!p)  continue;
71                 h.insert(p->str);
72                 p = p->next;
73             }
74             *this = h;
75             return;
76         }
77 
78 
79 };
80 
81 int main()
82 {
83     int op;
84     string s;
85     HashTable h;
86     while(cin >> op >> s) {
87         switch(op) {
88             case 1: h.insert(s); break;
89             case 2: cout << "find " << s << "in h : " << h.find(s) << endl; break;
90 
91         }
92     }
93 
94     return 0;
95 }
拉链法

4. 再hash 法,需要收集足够多hash 转换方法,将高维数据 映射成低维数据;

另外在STL 中对于基于哈希表的数据结构,在初始化中,自定义数据结构要提供对应的hasher方法;

======================= **经典问题** =======================
======================= **应用场景** =======================

1. STL 中  unordered_map/unordered_set/unordered_multimap/unordered_multiset  实现都是通过哈希表实现;

2. 布隆过滤器: 大数据(爬虫,url 重复判定);  信息安全有要求(因为即使拿到存储的数据,也无法判断原始数据);

3. 哈希链表实现 LRU(Least Recently Used); 里面应用复杂链表(剑指 Offer 35. 复杂链表的复制);

  1 //哈希表,以及LRU 不断更新关系,全部自己实现;冲突处理采用拉链法,大数据时候超时,主要还是hashFunc/冲突处理都太粗糙了;
  2 //不过主要锻炼自己能力,leetcode146 也有用现有容器,实现封装;
  3 // 
  4 
  5  class LRUCache {
  6     struct Node {
  7         Node(int k = -2, int v = -2): key(k), val(v),
  8         prev(nullptr), next(nullptr), Hprev(nullptr), Hnext(nullptr) {}
  9 
 10         Node(int k, int v, Node* HP): key(k), val(v),
 11         prev(nullptr), next(nullptr), Hprev(HP), Hnext(nullptr) {
 12             HP->Hnext = this;
 13         }
 14         void remove_this() {
 15             prev->next = next;
 16             next->prev = prev;
 17             prev = nullptr;
 18             next = nullptr;
 19             return;
 20         }
 21 
 22         void insert_prev(Node *pn) {
 23             prev->next = pn;
 24             pn->prev = prev;
 25             pn->next = this;
 26             prev = pn;
 27             return;
 28         }
 29 
 30         void pop_next() {
 31             Node *rp = next;
 32             rp->remove_this();
 33 
 34             rp->Hprev->Hnext = rp->Hnext;
 35             if(rp->Hnext) rp->Hnext->Hprev = rp->Hprev;
 36             delete rp;
 37             rp = nullptr;
 38             return;
 39         }
 40 
 41         int key, val;
 42         Node *prev, *next, *Hprev, *Hnext;   //H:同一组index 对应的关系;
 43     };
 44 public:
 45     int capacity, size;
 46     vector<Node*> addr;
 47     Node *head, *end;
 48 
 49     int hashFunc(int key) {
 50         return key;
 51     }
 52     LRUCache(int capacity): capacity(capacity), size(0),
 53     addr(capacity, new Node()), head(new Node()), end(new Node()){
 54         head->next = end;
 55         head->prev = end;
 56         end->prev = head;
 57         end->next = head;
 58     }
 59 
 60     void update_seq(Node *temp) {
 61         end->insert_prev(temp);
 62         if(size > capacity){
 63             head->pop_next();
 64             size -= 1;
 65         }
 66         return;
 67     }
 68 
 69     int get(int key) {
 70         int ret = -1;
 71         int index = hashFunc(key) % capacity;
 72         Node *temp  = addr[index];
 73         while(temp->Hnext && temp->Hnext->key != key) temp = temp->Hnext;
 74         if(temp->Hnext) {
 75             ret = temp->Hnext->val;
 76             temp->Hnext->remove_this();
 77             update_seq(temp->Hnext);
 78         }
 79         return ret;
 80     }
 81 
 82     void put(int key, int value) {
 83         int index = hashFunc(key) % capacity;
 84         Node *temp = addr[index];
 85         while(temp->Hnext && temp->Hnext->key != key) temp = temp->Hnext;
 86         if(temp->Hnext) {
 87             temp = temp->Hnext;
 88             temp->val = value;
 89             temp->remove_this();
 90         } else {
 91             temp = new Node(key, value, temp);
 92             size += 1;
 93         }
 94         update_seq(temp);
 95     }
 96 };
 97 
 98 /**
 99  * Your LRUCache object will be instantiated and called as such:
100  * LRUCache* obj = new LRUCache(capacity);
101  * int param_1 = obj->get(key);
102  * obj->put(key,value);
103  */
个人封装LRU

4. 哈希函数 对于 文本串匹配中的应用(单模匹配):

  文本串长度为 n, 模式串长度为 m, 暴力匹配时间复杂度为 O(n * m);

  使用hash 函数映射模式串,然后将 文本串分别使用哈希函数,并与模式串hash值比较,如果相同,进行暴力匹配;

  这里对于hash 函数,最好是能够减少计算次数,包含滑动窗口法的hash 函数最好,每次只需要 减去前面移出一位,加上 后面新进一位;

  如果hash 值范围为 p, 时间复杂度为: O( n + n / p *  m); //n: 遍历文本串求hash 值, n / p * m : 文本串中匹配并进行暴力匹配次数;

  如果p 足够大,每种组合都对应不一样的hash 值,则时间复杂度为 O(n + m) (遍历文本串做hash, 以及一次暴力匹配);

5. 作为相互映射关系,实现相互链接;(数组是 展开的函数; 函数是 压缩的数组; 哈希实现高维数据 到 低维数据 映射; --> 哈希表实现了复杂结构(高维数据)的 展开)

535. TinyURL 的加密与解密

 1 class Solution {
 2 public:
 3     unordered_map<string, string> arr;
 4     // Encodes a URL to a shortened URL.
 5     string encode(string longUrl) {
 6         string cur = "http://tinyurl.com/" + longUrl.substr(longUrl.rfind("/"));
 7         arr[cur] = longUrl;
 8         return cur;
 9     }
10 
11     // Decodes a shortened URL to its original URL.
12     string decode(string shortUrl) {
13         return arr[shortUrl];
14     }
15 };
16 
17 // Your Solution object will be instantiated and called as such:
18 // Solution solution;
19 // solution.decode(solution.encode(url));
发散思维;联系前面知识点
posted on 2022-03-03 21:49  学海一扁舟  阅读(230)  评论(0编辑  收藏  举报