摘要：
2010-03-02 10:381.问题：StringBuilder strSql = new StringBuilder();strSql.Append( "select * from WS_Class ");strSql.Append( " where ClassID= @ClassID ");SqlParameter[] parameters = {new SqlParameter( "@ClassID ", SqlDbType.Int,4)};parameters[0].Value = ClassID;return DbHel 阅读全文
posted @ 2011-12-29 22:17
BlueAmbition
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