实验1 C语言输入输出和简单程序编写
实验一
1 #include <stdio.h> 2 #include <stdlib.h> 3 int main() 4 { 5 printf(" O O \n"); 6 printf("<H> <H> \n"); 7 printf("I I I I \n"); 8 9 system("pause"); 10 return 0; 11 12 }
1 #include <stdio.h> 2 #include <stdlib.h> 3 int main() 4 { 5 printf(" O \n"); 6 printf("<H> \n"); 7 printf("I I \n"); 8 printf(" O \n"); 9 printf("<H> \n"); 10 printf("I I \n"); 11 12 system("pause"); 13 return 0; 14 15 }
1 #include <stdio.h> 2 int main() 3 { 4 double a, b, c; 5 scanf("%lf%lf%lf", &a, &b, &c); 6 7 if(a + b > c&&a +c > b&&b + c > a) 8 printf("能构成三角形\n"); 9 else 10 printf("不能构成三角形\n"); 11 return 0; 12 }
1 #include <stdio.h> 2 int main() 3 { 4 char ans1, ans2; 5 printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有,输入n或N表示没有) : "); 6 ans1 = getchar(); 7 getchar(); 8 printf("\n动手敲代码实践了没? (输入y或Y表示敲了,输入n或N表示木有敲) : "); 9 ans2 = getchar(); 10 if ((ans1==89|| ans1==121) && (ans2== 89 || ans2== 121)) 11 printf("\n罗马不是一天建成的, 继续保持哦:)\n"); 12 else 13 printf("\n罗马不是一天毁灭的, 我们来建设吧\n"); 14 return 0; 15 }
1 #include<stdio.h> 2 3 int main() 4 { 5 double x, y; 6 char c1, c2, c3; 7 int a1,a2, a3; 8 9 scanf("%d%d%d",&a1,&a2,&a3); 10 printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3); 11 12 scanf(" %c%c%c",&c1,&c2,&c3); 13 printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3); 14 15 scanf("%lf%lf",&x,&y); 16 printf("x = %f, y = %lf\n", x, y); 17 18 return 0; 19 }
1 #include <stdio.h> 2 3 int main() 4 { 5 int year; 6 double s; 7 s = 10e+8; 8 year = s / 31536000 + 0.5; 9 10 printf("10亿秒约等于%d年\n", year); 11 return 0; 12 }
1 #include <stdio.h> 2 #include <math.h> 3 int main() 4 { 5 double x, ans; 6 7 scanf("%lf", &x); 8 ans = pow(x, 365); 9 printf("%.2f的365次方: %.2f\n", x, ans); 10 return 0; 11 }
1 #include<stdio.h> 2 #include<math.h> 3 int main() 4 { 5 double F,C; 6 while (scanf("%lf", &C)!=EOF) 7 { 8 9 F = 9 * C / 5 + 32; 10 printf("摄氏度c=%.2f时,华氏度f=%.2f", C, F); 11 printf("\n"); 12 } 13 return 0; 14 }
1 #include<stdio.h> 2 #include<math.h> 3 int main() 4 { 5 int a, b, c; 6 double area,s; 7 while (scanf("%d%d%d",&a,&b,&c) != EOF) 8 { 9 s = (a + b + c) / 2.0; 10 area = sqrt(s * (s - a) * (s - b) * (s - c)); 11 printf("a=%d,b=%d,c=%d,area=%.3f", a, b, c,area); 12 printf("\n"); 13 } 14 return 0; 15 }
实验结果