实验五

 

#include <stdio.h>
#define N 5
void output(int x[], int n);
int main()
{
    int x[N] = {9, 55, 30, 27, 22};
    int i;
    int k; // 用于记录最大元素的下标
    int t; // 用作交换两个数组元素的中间变量
    printf("original array:\n");
    output(x, N);
    k = 0;
    for(i=1; i<N; ++i)
    if(x[i] > x[k])
    k = i;
    if(k != N-1)
    {
        t = x[N-1];
        x[N-1] = x[k];
        x[k] = t;
    }
    printf("after swapped:\n");
    output(x, N);
    return 0;
}
void output(int x[], int n)
{
    int i;
    for(i=0; i<n; ++i)
    printf("%d ", x[i]);
    printf("\n");
}

  

 

#include <stdio.h>
#define N 5
void output(int x[], int n);
int main()
{
    int x[N] = {9, 55, 30, 27, 22};
    int i;
    int t; // 用作交换两个数组元素的中间变量
    printf("original array:\n");
    output(x, N);
    for(i=0; i<N-1; ++i)
    if(x[i] > x[i+1])
    {
        t = x[i];
        x[i] = x[i+1];
        x[i+1] = t;
    }
    printf("after swapped:\n");
    output(x, N);
    return 0;
}
void output(int x[], int n)
{
    int i;
    for(i=0; i<n; ++i)
    printf("%d ", x[i]);
    printf("\n");
}

  

 

#include <stdio.h>
#define N 5
int binarySearch(int x[], int n, int item); // 函数声明
int main()
{
    int a[N] = {2, 7, 19, 45, 66};
    int i, index, key;
    printf("数组a中的数据:\n");
    for (i = 0; i < N; i++)
    printf("%d ", a[i]);
    printf("\n");
    printf("输入待查找的数据项: ");
    scanf("%d", &key);
    // 调用函数binarySearch()在数组a中查找指定数据项key,并返回查找结果给index
    index=binarySearch(a,N,key) ;
    if (index >= 0)
    printf("%d 在数组中,下标为%d\n", key, index);
    else
    printf("%d 不在数组中\n", key);
    return 0;
}
//函数功能描述:
//使用二分查找算法在数组x中查找特定值item,数组x大小为n
// 如果找到,返回其下标
// 如果没找到,返回-1
int binarySearch(int x[], int n, int item)
{
    int low, high, mid;
    low = 0;
    high = n - 1;
    while (low <= high)
    {
        mid = (low + high) / 2;
        if (x[mid]==item)
        return mid;
        else if (x[mid]>item)
        high = mid - 1;
        else
    low = mid + 1;
    }
    return -1;
}

  

// 练习:使用选择排序算法对字符串按字典序排序
#include <stdio.h>
#include<string.h>
#define N 5
void selectSort(char str[][20], int n); // 函数声明,两维数组作为函数参数
int main()
{
char name[][20] = {"Bob", "Bill", "Joseph", "Taylor", "George"};
int i;
printf("输出初始名单:\n");
for (i = 0; i < N; i++)
printf("%s\n", name[i]);
selectSort(name, N); // 调用选择法对name数组中的字符串排序
printf("按字典序输出名单:\n");
for (i = 0; i < N; i++)
printf("%s\n", name[i]);
return 0;
}
// 函数定义
// 函数功能描述:使用选择法对二维数组str中的n个字符串按字典序排序
void selectSort(char str[][20], int n)
{
int a, b, c;
    char temp[20];
    for (a=0; a<n-1; a++)
    {
        c = a; 
        for (b= a+1; b<n;b++)
        {
            if (strcmp(str[c], str[b]) > 0)
                c=b;
        }
            if (c!=a)
            { 
                strcpy(temp, str[c]);
                strcpy(str[c], str[a]);
                strcpy(str[a], temp);
            }
    }
}

  

 

#include <stdio.h>
int main()
{
int n;
int *pn;
n = 42;
pn = &n;
printf("&n = %#x, n = %d\n", &n, n);
printf("&pn = %#x, pn = %#x\n", &pn, pn);
printf("*pn = %d\n", *pn);
return 0;
}

  

 

1.   62fe1c ,42 

 2.62fe10,n的地址

3.n的值

#include <stdio.h>
#define N 5
int main()
{
int a[N] = {1, 9, 2, 0, 7};
int i;
int *p;
for(i=0; i<N; ++i)
printf("&a[%d] = %#x, a[%d] = %d\n", i, &a[i], i, a[i]);
printf("\n");
for(i=0; i<N; ++i)
printf("a+%d = %#x, *(a+%d) = %d\n", i, a+i, i, *(a+i));
printf("\n");
p = a;
for(i=0; i<N; ++i)
printf("p+%d = %#x, *(p+%d) = %d\n", i, p+i, i, *(p+i));
return 0;
}

  

 

 1.都可以

2.也都可以

posted @ 2021-12-15 00:08  要比我快乐  阅读(5)  评论(1编辑  收藏  举报