BMan、 - 博客园

POJ 3169 Layout 差分约束系统

摘要： //#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pii;#define pb(a) push(a)#define INF 阅读全文

posted @ 2014-04-05 22:55 BMan、阅读(136) 评论(0) 推荐(0)

POJ 3723 Conscription 最小生成树

摘要：想清楚后能发现就要让我们求最小生成树（如果图连通的话，否则就是森林）//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pi 阅读全文

posted @ 2014-04-05 21:28 BMan、阅读(166) 评论(0) 推荐(0)

POJ 3255 Roadblocks 次短路

摘要：和Dijksta求最短路一样，只是要维护两个数组：最短路d1,次短路d2。然后更新的时候注意细节。//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull; 阅读全文

posted @ 2014-04-05 20:45 BMan、阅读(172) 评论(0) 推荐(0)

UVA 11367 Full Tank? 最短路

摘要：以状态（u,fuel)为结点建图（把每个点拆成100个），表示在点u时还剩下fuel个单位的燃料，那么状态就可以这样转移：(u,fuel)->(u,fuel+i) ：加i单位的燃料，所以这条边的权值就是 i*p[u];(u,fuel) ->(v,fuel-dist): 走到另一个点，其中dist为路径。当然直接这样做可能会超时，需要做两个小优化（做其中一个就能AC了）1. (u,fuel)->(u,fuel+i) 中的i只需为1就行了，这样就能边数从100^2降到100. 比如(u,fuel)->(u,fuel+3)可以用 (u,fuel)->(u,fuel+1 阅读全文

posted @ 2014-04-05 19:31 BMan、阅读(206) 评论(0) 推荐(0)

UVA 10269 Adventure of Super Mario 最短路

摘要：（i,j)表示当前在结点j，还剩下i次使用魔法的机会。以(i,j)为结点建图，求最短路。//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typed 阅读全文

posted @ 2014-04-05 13:30 BMan、阅读(157) 评论(0) 推荐(0)

UVA 10603 Fill 最短路

摘要： //#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pii;#define pb(a) push(a)#define INF 阅读全文

posted @ 2014-04-05 13:28 BMan、阅读(160) 评论(0) 推荐(0)

POJ 2431 Expedition 优先队列

摘要：由于油箱是无限的，所以每次经过加油站都不选择加油，等到后面油不够了，再来“反悔”，把前面经过的油站的油加上，尽可能选量大的,用优先队列维护。//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef un 阅读全文

posted @ 2014-04-04 17:01 BMan、阅读(158) 评论(0) 推荐(0)

POJ 3253 Fence Repair 贪心

摘要：每次合并选最短的两块木板，用优先队列优化。//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pii;#define pb( 阅读全文

posted @ 2014-04-04 16:02 BMan、阅读(138) 评论(0) 推荐(0)

POJ 3609 Saruman's Army 贪心

摘要：从坐开始，贪心选择每个点标记还是不标记。//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pii;#define pb(a 阅读全文

posted @ 2014-04-04 15:50 BMan、阅读(276) 评论(0) 推荐(0)

POJ 3617 Best Cow Line 贪心

摘要：不能单纯比较头尾两个字符，应该比较头尾两个字符串。//#pragma comment(linker, "/STACK:1024000000,1024000000")#include#include#include#include#include#include#include#include#include#include#include#include#include#includeusing namespace std;typedef long long ll;typedef unsigned long long ull;typedef pair pii;#define 阅读全文

posted @ 2014-04-04 15:33 BMan、阅读(141) 评论(0) 推荐(0)

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