摘要:
1 class Solution 2 { 3 public://saeed ssaaedd 4 bool isLongPressedName(string name, string typed) 5 { 6 int typedEnd = 0; 7 for(int i = 0;i = typed.... 阅读全文
摘要:
1 class Solution 2 { 3 public: 4 int minFlipsMonoIncr(string S) 5 { 6 vector left2CountOne (S.size(),0); 7 vector right2CountZero (S.size(),0); 8 ... 阅读全文