随笔分类 - Hangzhou Dianzi University OJ
摘要:1 #include 2 #define _for(i,a,b) for(int i = (a);i >=1; 17 } 18 return ans; 19 } 20 int main() 21 { 22 ll liusi[70]; 23 while(~scanf("%lld",&liusi[0])) 24 { 25 _for(i,1...
阅读全文
摘要:1 #include 2 #define _for(i,a,b) for(int i = (a);i > tmp) 9 { 10 int sz = tmp.size(); 11 12 int m; 13 scanf("%d",&m); 14 int sum = 0; 15 _for(i,0,m) 1...
阅读全文
摘要:1 #include 2 #define pb push_back 3 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 4 #define INF 0x3f3f3f3f 5 #define sz size() 6 7 using namespace std; 8 typedef long long ll; 9 #defin...
阅读全文
摘要:1 #include 2 #include 3 #define pb push_back 4 #define _for(i,a,b) for(int i = (a);i 0) 27 { 28 k = (k-1)/2; 29 dat[k] = dat[k*2+1]+dat[k*2+2]; 30 } 31 } 32 33 //求(a,b)...
阅读全文
摘要:垃圾题,对于都是负数的情况,居然不是输出0,题干简直形同虚设
阅读全文
摘要:#include #define pb push_back #define _for(i,a,b) for(int i = (a);i b.s; } }; int main() { Mouse a[1003]; int aend = 0; int c,d; while(~scanf("%d %d",&c,&d)) { a[ae...
阅读全文
摘要:1 #include 2 #define pb push_back 3 #define _for(i,a,b) for(int i = (a);i = 1;i --) cout 0;) {s[++len] = inte%10;inte /= 10;}; 34 return (*this); 35 } 36 37 HP HP::operator * (const H...
阅读全文
摘要:1 #include 2 #define pb push_back 3 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 4 #define INF 0x3f3f3f3f 5 6 using namespace std; 7 8 const int maxn = 5003; 9 10 long long solve(lo...
阅读全文
摘要:1 #include 2 #define pb push_back 3 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 4 #define INF 0x3f3f3f3f 5 6 using namespace std; 7 8 const int maxn = 5003; 9 10 int main() 11 { 12...
阅读全文
摘要:1 #include 2 #define pb push_back 3 #define _for(i,a,b) for(int i = (a);i < (b);i ++) 4 #define INF 0x3f3f3f3f 5 6 using namespace std; 7 8 const int maxn = 5003; 9 10 int main() 11 { 12...
阅读全文
摘要:1 #include 2 using namespace std; 3 4 #define pb push_back 5 #define maxSize 3939 6 #define _for(i,a,b) for(int i = (a);i list; 22 int num; 23 while(~scanf("%d",&num) && num!=0) 24 ...
阅读全文
摘要:1 #include 2 #define _for(i,a,b) for(int i = (a);i G[MAXV]; 8 9 int dfs(int u) 10 { 11 if(Vis[u]) return 0; 12 Vis[u] = 1; 13 int sz = G[u].size(),r = sz&0x1; 14 _for(i,0,sz) r...
阅读全文
摘要:首先,给大家一些测试数据 2 1 4 G 10 5 R 6 4 3 1 5 H 4 5 G 10 5 C 7 5 4 1 4 H 3 2 G 10 5 R 3 3 R 2 1 4 1 4 G 10 5 C 9 4 C 8 4 C 2 4 4 2 5 H 2 3 R 1 1 G 10 4 H 3 8
阅读全文
摘要:1 #include 2 #include 3 #include 4 #include 5 #include 6 7 using namespace std; 8 int main() 9 { 10 int T; 11 scanf("%d",&T); 12 while(T--) 13 { 14 long long in...
阅读全文
摘要:1 #include 2 #include 3 #include 4 #include 5 #include 6 #include 7 #include 8 9 using namespace std; 10 int main() 11 { 12 int N; 13 string HDU = "HDU"; 14 while(cin >> ...
阅读全文

浙公网安备 33010602011771号