C#中OpenFileDialog的使用
摘要:
string resultFile = ""; OpenFileDialog openFileDialog1 = new OpenFileDialog(); openFileDialog1.InitialDirectory = "D:\\Patch"; openFileDialog1.Filter ... 阅读全文
posted @ 2015-12-17 23:09 大西瓜3721 阅读(671) 评论(0) 推荐(0)
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