“红明谷”杯数据安全大赛 技能场景赛 部分wp

MISC 我的心是冰冰的

描述:似乎有信息被隐藏了。

1.首先,思路是盲猜用图中的信息解压缩包的密码

另一边用zip爆破工具爆破,节省时间,爆破居然先爆破出来了

密码是:gnibgnib

 

2.然后分析bingbing.pcapng

打开后发现是usb键盘流量,或者是usb鼠标流量

网上查资料可得,USB协议的数据部分在Leftover Capture Data域之中,右键leftover capture data –> 应用为列,可以将该域的值在主面板上显示,键盘数据包的数据长度为8个字节,击键信息集中在第3个字节,每次key stroke都会产生一个keyboard event usb packet

 

可以将 leftover capture data单独提取出来,linux中,具体命令为:

tshark -r bingbing.pcap -T fields -e usb.capdata > usbdata.txt

 

 

 

 

 

因此,这就是usb键盘流量

3.从得出的userdata.txt文件中过滤出键盘击键相关的流量,并根据映射表,将键盘按键按照对应关系输出出来,查资料找到了网上的脚本

 

  1 #!/usr/bin/env python
  2 
  3 import sys
  4 
  5 import os
  6 
  7  
  8 
  9 DataFileName = "usbdata.txt"
 10 
 11  
 12 
 13 presses = []
 14 
 15  
 16 
 17 normalKeys = {"04":"a", "05":"b", "06":"c", "07":"d", "08":"e", "09":"f", "0a":"g", "0b":"h", "0c":"i", "0d":"j", "0e":"k", "0f":"l", "10":"m", "11":"n", "12":"o", "13":"p", "14":"q", "15":"r", "16":"s", "17":"t", "18":"u", "19":"v", "1a":"w", "1b":"x", "1c":"y", "1d":"z","1e":"1", "1f":"2", "20":"3", "21":"4", "22":"5", "23":"6","24":"7","25":"8","26":"9","27":"0","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"-","2e":"=","2f":"[","30":"]","31":"\\","32":"<NON>","33":";","34":"'","35":"<GA>","36":",","37":".","38":"/","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}
 18 
 19  
 20 
 21 shiftKeys = {"04":"A", "05":"B", "06":"C", "07":"D", "08":"E", "09":"F", "0a":"G", "0b":"H", "0c":"I", "0d":"J", "0e":"K", "0f":"L", "10":"M", "11":"N", "12":"O", "13":"P", "14":"Q", "15":"R", "16":"S", "17":"T", "18":"U", "19":"V", "1a":"W", "1b":"X", "1c":"Y", "1d":"Z","1e":"!", "1f":"@", "20":"#", "21":"$", "22":"%", "23":"^","24":"&","25":"*","26":"(","27":")","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"_","2e":"+","2f":"{","30":"}","31":"|","32":"<NON>","33":"\"","34":":","35":"<GA>","36":"<","37":">","38":"?","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}
 22 
 23  
 24 
 25 def main():
 26 
 27     # check argv
 28 
 29     if len(sys.argv) != 2:
 30 
 31         print "Usage : "
 32 
 33         print "        python UsbKeyboardHacker.py data.pcap"
 34 
 35         print "Tips : "
 36 
 37         print "        To use this python script , you must install the tshark first."
 38 
 39         print "        You can use `sudo apt-get install tshark` to install it"
 40 
 41         print "Author : "
 42 
 43         print "        Angel_Kitty <angelkitty6698@gmail.com>"
 44 
 45         print "        If you have any questions , please contact me by email."
 46 
 47         print "        Thank you for using."
 48 
 49         exit(1)
 50 
 51  
 52 
 53     # get argv
 54 
 55     pcapFilePath = sys.argv[1]
 56 
 57     
 58 
 59     # get data of pcap
 60 
 61     os.system("tshark -r %s -T fields -e usb.capdata > %s" % (pcapFilePath, DataFileName))
 62 
 63  
 64 
 65     # read data
 66 
 67     with open(DataFileName, "r") as f:
 68 
 69         for line in f:
 70 
 71             presses.append(line[0:-1])
 72 
 73     # handle
 74 
 75     result = ""
 76 
 77     for press in presses:
 78 
 79         Bytes = press.split(":")
 80 
 81         if Bytes[0] == "00":
 82 
 83             if Bytes[2] != "00":
 84 
 85                 result += normalKeys[Bytes[2]]
 86 
 87         elif Bytes[0] == "20": # shift key is pressed.
 88 
 89             if Bytes[2] != "00":
 90 
 91                 result += shiftKeys[Bytes[2]]
 92 
 93         else:
 94 
 95             print "[-] Unknow Key : %s" % (Bytes[0])
 96 
 97     print "[+] Found : %s" % (result)
 98 
 99  
100 
101     # clean the temp data
102 
103     os.system("rm ./%s" % (DataFileName))
104 
105  
106 
107  
108 
109 if __name__ == "__main__":
110 
111 main()

 

最后结果从<DEL>分段分别解密文, 16进制解码即可

flag值: flag{8f9ed2f933ef14a8d0523d0349e1299c}

总结:挺有劲儿的一题,做了好久,明明答案早已经出来了,开始却没发现那是16进制,辗转了好久,以为是脚本错了,折腾好久,最后才想到答案可能是密文,提交答案时却是第10名提交的,错失前三血

 

MISC 签到

答对8道数据安全知识小竞赛题,得flag

 

 

 

flag值: flag{7e63095d-4310-4f24-a01a-4a858d442fab}

 

赛后感受:题目好多不会做,还是很自闭了,感谢队友的辅助,一起加油!

posted @ 2021-04-03 00:08  Alanpipi*  阅读(852)  评论(0编辑  收藏  举报