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Codeforces Beta Round #55 (Div. 2)

B题

#include <iostream>
#include<stdio.h>
#include<string.h>
using namespace std;

int main()
{
int n,a,sum=0,min=101;
scanf("%d",&n);
while(n--)
{
scanf("%d",&a);
sum+=a;
if(a%2==1&&a<min)
{
min=a;
}
}
if(sum%2==1)printf("%d\n",sum);
else if(min<101)printf("%d\n",sum-min);
else printf("0\n");
return 0;
}
AC code

C题:

#include <iostream>
#include<stdio.h>
#include <string.h>
#include <math.h>

using namespace std;

int main()
{
    char s1[105];
    char s2[105];
    int zimu[27];
    char out[105];
    int n;
    while(scanf("%d",&n)!=EOF)
    {
        memset(zimu,0,sizeof(zimu));
        scanf("%s",s2);
        int L=strlen(s2);
        strcpy(s1,s2);
        _strrev(s2);

        int judge=1;
        for(int i=0;i<L;i++)
        {
            if(s1[i]!='?')
            {
                zimu[s1[i]-'a']=1;
            }
            if(s1[i]!=s2[i])
            {
                if(s1[i]=='?')
                {
                    s1[i]=s2[i];
                    //printf("s1  %c %d\n",s1[i],i);
                }
                else if(s2[i]=='?')
                {
                    s2[i]=s1[i];
                }
                else
                {
                    judge=0;
                    break;
                }
            }
        }

       /*for(int i=0;i<L;i++)
        printf("%c",s2[i]);
        printf("###\n");

        for(int i=0;i<L;i++)
        printf("%c",s1[i]);
        printf("***\n");*/

        if(judge==0){printf("IMPOSSIBLE\n");}
        else
        {
            for(int j=L/2;j>=0;j--)
            {

                if(s1[j]=='?')
                {
                    int i;
                    for(i=n-1;i>=0;i--)
                    {
                        if(zimu[i]!=1)
                        {
                            out[j]=i+'a';
                            s1[j]=i+'a';
                            out[L-j-1]=i+'a';
                            s1[L-j-1]=i+'a';
                            zimu[i]=1;
                            break;
                        }
                    }
                    if(i==-1)
                    {
                        out[j]='a';
                        out[L-j-1]='a';
                    }
                }
                else {
                    out[j]=s1[j];
                    out[L-j-1]=s1[L-j-1];
                }

            }

            int j;
            for(j=0;j<n;j++)
            {
                if(zimu[j]!=1)break;
            }
            if(j==n){
            for(int k=0;k<L;k++)
            {
                printf("%c",out[k]);
            }
            printf("\n");
            }
            else printf("IMPOSSIBLE\n");
        }
    }
    return 0;
}
C题 ac code

D题:

/********************
AC
Time:2013-10-30
*******************************/
#include <iostream>
#include<stdio.h>
#include<string.h>
#include<math.h>
#include <algorithm>
using namespace std;
int num[100003][4];
int nnum[300010];
int num1[100003];

int min(int a,int b,int c)
{
    if(nnum[a]<=nnum[b]&&nnum[a]<=nnum[c])
    {
        return a;
    }
    else if(nnum[b]<=nnum[a]&&nnum[b]<=nnum[c])
    return b;
    else
     return c;
}
int main()
{
    int n;
    int i,j,k;
    int mnum;
    while(scanf("%d",&n)!=EOF)
    {
        int judge=0;
        for(i=1;i<=3*n;i++)
        {
            scanf("%d",&mnum);
            nnum[mnum]=i;
        }
        for(i=1;i<=n;i++)
        {
            scanf("%d %d %d",&num[i][1],&num[i][2],&num[i][3]);
            num[i][0]=min(num[i][1],num[i][2],num[i][3]);
        }
        scanf("%d",&k);
        for(i=1;i<=n;i++)
        {
            if(num[i][0]==k)
            {
                judge=1;
                break;
            }
        }
        if(judge==0)
        {
            for(i=1;i<3*n;i++)
            {
                if(i!=k)
                printf("%d ",i);
            }
            printf("%d\n",3*n);
        }
        else
        {
            int m=0;
            int judge2=0;
            for(i=1;i<=n;i++)
            {
                for(j=1;j<=3;j++)
                {
                    if(num[i][j]!=k)
                    num1[m++]=num[i][j];
                    else
                    judge2=1;
                }
                if(judge2==1)break;
            }
            sort(num1,num1+m);
            int duiyuan=0;
            for(j=0;j<m&&duiyuan<2;j++)
            {
                if(num1[j]==num[i][1]||num1[j]==num[i][2]||num1[j]==num[i][3])
                duiyuan++;
            }
                for(int ii=i+1;ii<=n;ii++)
                {
                    for(int jj=1;jj<=3;jj++)
                    {
                        num1[m++]=num[ii][jj];
                    }
                }
            if(i!=n)sort(&num1[j],num1+m);

            for(int ii=0;ii<m;ii++)
            {
                if(ii!=0)
                printf(" ");
                printf("%d",num1[ii]);
            }
            printf("\n");

        }
    }
    return 0;
}
D题 ac code

 

 

posted on 2013-11-08 10:54  点A点C  阅读(281)  评论(0编辑  收藏  举报

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