View Code #include<cstdio>#include<cstring>int q[103], p[103], s[103], pp[103];int n, k, a, b;int main(){ int i, j; scanf("%d%d", &n, &k); for(i = 1; i <= n; i++) scanf("%d", &q[i]); for(i = 1; i <= n; i++) scanf("%d", &s[i]); //求解操作1的周 Read More
posted @ 2012-12-07 19:59
To be an ACMan
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失算啊,水题啊,比赛没AView Code #include<cstdio>#include<cstring>#include<algorithm>using namespace std;int a[100005], b[100005];int main(){ int i, j, n; scanf("%d", &n); for(i = 0; i < n ;i++) scanf("%d", &a[i]), b[i] = a[i]; if(n <= 2) { puts("-1" Read More
posted @ 2012-12-07 16:17
To be an ACMan
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比赛时我用单调队列A的View Code #include<cstdio>#include<cstring>#include<queue>using namespace std;#define LL __int64int a, n, d;LL ans;queue <int> q;int main() { int i, j; scanf("%d%d", &n, &d); for(i = 0; i < n; i++) { scanf("%d", &a); q.push(a); wh Read More
posted @ 2012-12-07 15:41
To be an ACMan
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