python 列表推导式 题二

补写list3被涂改的内容

 

 

结果如下：

list1 = ["1.Just do it", "2.一切皆有可能", "3.让编程改变世界", "Impossible is Nothing"]
list2 = ["4.阿迪达斯", "2.李宁", "3.python", "1.耐克"]
list3 = [name + ":" + slogan[2:] for slogan in list1 for name in list2  if slogan[0]==name[0]]

print(list3)
for each in list3:
    print(each)

列表推导式还原如下：

list1 = ["1.Just do it", "2.一切皆有可能", "3.让编程改变世界", "Impossible is Nothing"]
list2 = ["4.阿迪达斯", "2.李宁", "3.python", "1.耐克"]
for slogan in list1:
                                #遍历list1内容 获取口号slogan
    for name in list2:
                                #遍历list2内容 获取品牌name
        if name[0] == slogan[0]:
                                #如果name里下标0的字符与slogan里下标0的字符相同
            list3 = name + ":" + slogan[2:]
                                #进行加法和切片
            print(list3)