类实现时间差

Problem A: 1,2,3班_Contest1_Q1

Time Limit: 1 Sec  Memory Limit: 128 MB Submit: 517  Solved: 142 [Submit][Status][Web Board]

Description

设定一个时间类，类中包含年、月、日，计算任意两个时间之间的天数，并显示出来。注意闰年与平年

类如下：

class Date

{

private:

     int year;

     int month;

     int day;

public:

     Date(void);

     Date(int year,int month,int day);

     ~Date(void);

     int getDateDiff(Date date2);

};

Input

从键盘上输入两个日期，如2012/02/02、2013/02/03

Output

打印两个日期之间的天数

 

Sample Input

2013/03/28
2013/04/08

Sample Output

11

HINT

#include<iostream>
using namespace std;
class Date
{
     int year;
     int month;
     int day;
	 bool prime;
public:
	Date(int y,int m,int d):year(y),month(m),day(d){
	if((year%4==0&&year%100!=0)||(year%400==0)) prime =  true;
	else prime = false;
	}
	Date(Date& it);
	int getyear(){return year;}
	int getmonth(){return month;}
	int getday(){return day;}
   friend int operator-(Date&date1,Date&date2);
    Date operator++();
	friend bool operator>(Date&date1,Date&date2);
};

Date::Date(Date&it){
	year = it.year;
	month = it.month;
	day = it.day;
	if((year%4==0 && year%100!=0)||(year%400==0)) prime =  true;
	else prime = false;
}
Date Date::operator++()
{
	if(day==28)
		{
		 if(prime) day++;
		 else if(month==2) { day = 1;month++;}
		 else day++;
	    }
	else if(day==29)
	     {
		  if(month==2) { day = 1;month++;}
		  else day++;   
	      }
	else if(day==30){
	    if(month==1||month==3||month==5||month==7||month==8||month==10||month==12)
		         day++;
		else {day=1;month++;} 
	}
	else if(day==31){
	   day=1;month++;
	}
	else day++;

	if(month==13) 
	{
	year++;
	month=1;
	if((year%4==0 && year%100!=0)||(year%400==0))  prime =  true;
	else prime = false;
	}
	return*this;
}

bool operator>(Date&date1,Date&date2)
{
	if(date1.getyear()>date2.getyear()) return true;
	else if(date1.getmonth()>date2.getmonth()) return true;
	else if(date1.getday()>date2.getday()) return true;
	else return false;
}



int operator-(Date&date1,Date&date2){
	int sum=0;
	Date maxdate = date1.getyear() > date2.getyear() ? date1:date2;
	Date mindate = date1.getyear() <= date2.getyear() ? date1:date2;
	int y = 0;
	for( y = mindate.getyear();y<maxdate.getyear()-1;y++)
      { if((y%4==0&&y%100!=0)||(y%400==0)) sum+=366;
		else sum+=365;
	   }

	Date datesome(y,mindate.getmonth(),mindate.getday());
    while(1)
	{
		if(maxdate > datesome) {sum++;++datesome;}
		else break;
	}
	return sum;
}

int main(){
int year,month,day;
cin>>year;
getchar();
cin>>month;
getchar();
cin>>day;

Date date01(year,month,day);

cin>>year;
getchar();
cin>>month;
getchar();
cin>>day;

Date date02(year,month,day);

int sum = date01 - date02;

cout<<sum<<endl;


}