实验1 c语言
#include #include int main() { printf(" o \n"); printf("\n"); printf("I I\n"); printf(" o \n"); printf("\n"); printf("I I\n"); system("pause"); return 0; }
#include <stdio.h> #include <stdlib.h> int main() { printf(" o \n"); printf("<H>\n"); printf("I I\n"); printf(" o \n"); printf("<H>\n"); printf("I I\n"); system("pause"); return 0; }

#include <stdio.h> int main() { printf(" o"); printf(" o\n"); printf("<H>"); printf("<H>\n"); printf("I I"); printf("I I\n"); return 0; }

#include <stdio.h> int main() { double a,b,c; scanf_s("%lf%lf%lf", &a, &b, &c); if (a+b>c && a+c>b && b+c>a) printf("能构成三角形\n"); else printf("不能构成三角形\n"); return 0; }

#include <stdio.h> int main() { char ans1, ans2;
printf("每次课前认真预习、课后及时复习了没? (输入y或Y表示有,输入n或N表示没有) : "); ans1 = getchar();
getchar(); printf("\n动手敲代码实践了没? (输入y或Y表示敲了,输入n或N表示木有敲) : "); ans2 = getchar(); if ((ans1=="y"||ans1=="Y")&&(ans2=="y"||ans2=="Y")) printf("\n罗马不是一天建成的, 继续保持哦:)\n"); else printf("\n罗马不是一天毁灭的, 我们来建设吧\n"); return 0; }

#include<stdio.h> int main() { double x, y; char c1, c2, c3; int a1, a2, a3; scanf_s("%d%d%d", &a1, &a2, &a3); printf("a1 = %d, a2 = %d, a3 = %d\n", a1, a2, a3); scanf_s("%c%c%c", &c1, &c2, &c3); printf("c1 = %c, c2 = %c, c3 = %c\n", c1, c2, c3); scanf_s("%lf,%lf", &x, &y); printf("x = %f, y = %lf\n", x, y); return 0; }

#include<stdio.h> int main() { int year; year = 1000000000 / (365 * 24 * 60 * 60); printf("10亿秒约等于%d年\n", year); return 0; }

#include <stdio.h> #include <math.h> int main() { double x, ans; while (scanf_s("%1f", &x) != EOF) { ans = pow(x, 365); printf("%.2f的365次方: %.2f\n", x, ans); printf("\n"); } return 0; }

#include <stdio.h> int main() { double C, F; while (scanf_s("%lf", &C) != EOF) { F = 9.0 / 5 * C + 32; printf("摄氏度c=%lf时,华氏度f=%lf", C, F); printf("\n"); } return 0; }

include <stdio.h> #include <math.h> int main() { int a, b, c; double area, p; while (scanf_s("%d %d %d", &a, &b, &c) != EOF) { p = (a + b + c) / 2; area = sqrt(p * (p - a) * (p - b) * (p - c)); printf("a=%d,b=%d,c=%d,area=%.3lf", a, b, c, area); printf("\n"); } return 0; }

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