#include<iostream>
#include<stdio.h>
#include<cstdio>
#include<vector>
#include <algorithm>
#include <functional>
#include<string>
#include<fstream>
#include <sstream>
#include <assert.h>
using namespace std;
class Solution {
public:
string longestPalindrome(string s)
{
if (s.length() < 0) return "";//如果长度小于0则返回空
int n = s.size();//获得字符串的长度
vector<vector<bool>> dp(n, vector<bool>(n, false));//定义bool向量
int maxlen = 1, start = 0;
for (int i = 0; i < n; i++)
{
for (int j = 0; j <= i; j++)
{
if (i - j < 2) dp[i][j] = (s[i] == s[j]);
else
dp[i][j] = (s[i] == s[j] && dp[i - 1][j + 1] == 1);
if (dp[i][j] && maxlen < i - j + 1)
{
maxlen = i - j + 1;
start = j;
}
}
}
return s.substr(start, maxlen);
}
};
string stringToString(string input) {
assert(input.length() >= 2);
string result;
for (int i = 1; i < input.length() - 1; i++) {
char currentChar = input[i];
if (input[i] == '\\') {
char nextChar = input[i + 1];
switch (nextChar) {
case '\"': result.push_back('\"'); break;
case '/': result.push_back('/'); break;
case '\\': result.push_back('\\'); break;
case 'b': result.push_back('\b'); break;
case 'f': result.push_back('\f'); break;
case 'r': result.push_back('\r'); break;
case 'n': result.push_back('\n'); break;
case 't': result.push_back('\t'); break;
default: break;
}
i++;
}
else {
result.push_back(currentChar);
}
}
return result;
}
int main() {
string line;
while (getline(cin, line)) {
string s = stringToString(line);
string ret = Solution().longestPalindrome(s);
string out = (ret);
cout << out << endl;
}
return 0;
}

# 给定一个字符串 s,找到 s 中最长的回文子串。你可以假设 s 的最大长度为 1000。
# 示例 1:
# 输入: "babad"
# 输出: "bab"
# 注意: "aba" 也是一个有效答案。
# 示例 2:
# 输入: "cbbd"
# 输出: "bb"
# 解题思路:
# 正着与倒着比.
import sys
class Solution:
def zuichanghuiwen(self, s):
if len(s) <= 1:
return s
for length in range(len(s), 0, -1):
for i in range(0, len(s) - length + 1):
now_s = s[i:i + length]
if now_s == now_s[::-1]:
return now_s
if __name__ == '__main__':
s = sys.stdin.readline().strip()
ret = Solution().zuichanghuiwen(s)
print(ret)