path的用法和所遇错误

首先上源代码:

def _path(route, view, kwargs=None, name=None, Pattern=None):
    if isinstance(view, (list, tuple)):
        # For include(...) processing.
        pattern = Pattern(route, is_endpoint=False)
        urlconf_module, app_name, namespace = view
        return URLResolver(
            pattern,
            urlconf_module,
            kwargs,
            app_name=app_name,
            namespace=namespace,
        )
    elif callable(view):
        pattern = Pattern(route, name=name, is_endpoint=True)
        return URLPattern(pattern, view, kwargs, name)
    else:
        raise TypeError('view must be a callable or a list/tuple in the case of include().')

从中可明白错误信息是在第17行,而错误原因则是意外参数或views没有tuple或list类型.

解决方案:则是让view里的函数返回的参数为tuple或者list即可