实验5

task1.1

编程代码

#include <stdio.h>
#define N 4
int main()
{
int x[N] = {1, 9, 8, 4};
int i;
int *p;
// 方式1:通过数组名和下标遍历输出数组元素
for (i = 0; i < N; ++i)
printf("%d", x[i]);
printf("\n");
// 方式2:通过指针变量遍历输出数组元素 (写法1)
for (p = x; p < x + N; ++p)
printf("%d", *p);
printf("\n");
// 方式2:通过指针变量遍历输出数组元素(写法2)
p = x;
for (i = 0; i < N; ++i)
printf("%d", *(p + i));
printf("\n");
// 方式2:通过指针变量遍历输出数组元素(写法3)
p = x;
for (i = 0; i < N; ++i)
printf("%d", p[i]);
printf("\n");
return 0;
}

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1.2

编程代码

#include <stdio.h>
#include<stdlib.h>
int main()
{
int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
int i, j;
int *p; // 指针变量,存放int类型数据的地址
int(*q)[4]; // 指针变量,指向包含4个int型元素的一维数组
// 使用数组名、下标访问二维数组元素
for (i = 0; i < 2; ++i)
{
for (j = 0; j < 4; ++j)
printf("%d", x[i][j]);
printf("\n");
} //使用指针变量p间接访问二维数组元素
for (p = &x[0][0], i = 0; p < &x[0][0] + 8; ++p, ++i)
{
printf("%d", *p);
if ((i + 1) % 4 == 0)
printf("\n");
}
// 使用指针变量q间接访问二维数组元素
for (q = x; q < x + 2; ++q)
{
for (j = 0; j < 4; ++j)
printf("%d", *(*q + j));
printf("\n");
}system("pause");
return 0;
}

 

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task2.1

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
#define N 80
int main()
{
char s1[] = "Learning makes me happy";
char s2[] = "Learning makes me sleepy";
char tmp[N];
printf("sizeof(s1) vs. strlen(s1): \n");
printf("sizeof(s1) = %d\n", sizeof(s1));
printf("strlen(s1) = %d\n", strlen(s1));
printf("\nbefore swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
printf("\nswapping...\n");
strcpy(tmp, s1);
strcpy(s1, s2);
strcpy(s2, tmp);
printf("\nafter swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
system("pause");
return 0;
}

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2   计算的是s1算上终止符号所有字符的个数    统计的是s1不算终止符的个数

不能  

更换

2.2

编程代码

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
#define N 80
int main()
{
char *s1 = "Learning makes me happy";
char *s2 = "Learning makes me sleepy";
char *tmp;
printf("sizeof(s1) vs. strlen(s1): \n");
printf("sizeof(s1) = %d\n", sizeof(s1));
printf("strlen(s1) = %d\n", strlen(s1));
printf("\nbefore swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
printf("\nswapping...\n");
tmp = s1;
s1 = s2;
s2 = tmp;
printf("\nafter swap: \n");
printf("s1: %s\n", s1);
printf("s2: %s\n", s2);
system("pause");
return 0;
}

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一串字符  s1中单词的个数  s1中不算终止符号所有字符的个数

可以

交换的是s1 和s2 的地址

交换了

task3

编程代码

#include <stdio.h>
#include<stdlib.h>
void str_cpy(char *target, const char *source);
void str_cat(char *str1, char *str2);
int main()
{
char s1[80], s2[20] = "1984";
str_cpy(s1, s2);
puts(s1);
str_cat(s1, " Animal Farm");
puts(s1);
system("pause");
return 0;
} void str_cpy(char *target, const char *source)
{
while (*target++ = *source++)
;
} void str_cat(char *str1, char *str2)
{
while (*str1)
str1++;
while (*str1++ = *str2++)
    ;}

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task4

编程代码

#include <stdio.h>
#include<stdlib.h>
#define N 80

int func(char *);
int main()
{
char str[80];
while (gets(str) != NULL)
{
if (func(str))
printf("yes\n");
else
printf("no\n");
} return 0;
} int func(char *str)
{
char *begin, *end;
begin = end = str;
while (*end)
end++;
end--;
while (begin < end)
{
if (*begin != *end)
return 0;
else
{
begin++;
end--;
}
}system("pause"); return 1;
}

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 task5 

编程代码

#include <stdio.h>
#include<stdlib.h>
#define N 80
void func(char *);
int main()
{
char s[N];
while (scanf("%s", s) != EOF)
{
func(s);
puts(s);
}
system("pause");
return 0;
}
void func(char *str)
{
int i;
char *p1, *p2, *p;
p1 = str;
while (*p1 == '*')
p1++;
p2 = str;
while (*p2)
p2++;
p2--;
while (*p2 == '*')
p2--;
p = str;
i = 0;
while (p < p1)
{
str[i] = *p;
p++;
i++;
}
while (p <= p2)
{
if (*p != '*')
{
str[i] = *p;
i++;
}
p++;
}
while (*p != '\0')
{
str[i] = *p;
p++;
i++;
}
str[i] = '\0';
}

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task6.1

#include <stdio.h>
#include <string.h>
void sort(char *name[], int n);
int main()
{
char *course[4] = {"C Program",
"C++ Object Oriented Program",
"Operating System",
"Data Structure and Algorithms"};
int i;
sort(course, 4);
for (i = 0; i < 4; i++)
printf("%s\n", course[i]);
return 0;
}
void sort(char *name[], int n)
{
int i, j;
char *tmp;
for (i = 0; i < n - 1; ++i)
for (j = 0; j < n - 1 - i; ++j)
if (strcmp(name[j], name[j + 1]) > 0)
{
tmp = name[j];
name[j] = name[j + 1];
name[j + 1] = tmp;
}
}

task6.2

编程代码

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
void sort(char *name[], int n);
int main()
{
char *course[4] = {"C Program",
"C++ Object Oriented Program",
"Operating System",
"Data Structure and Algorithms"};
int i;
sort(course, 4);
for (i = 0; i < 4; i++)
printf("%s\n", course[i]);
system("pause");
return 0;

}
void sort(char *name[], int n)
{
int i, j, k;
char *tmp;
for (i = 0; i < n - 1; i++)
{
k = i;
for (j = i + 1; j < n; j++)
if (strcmp(name[j], name[k]) < 0)
k = j;
if (k != i)
{
tmp = name[i];
name[i] = name[k];
name[k] = tmp;
}
}
}

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储存位置发生了变化

task7

编程代码

#include <stdio.h>
#include <string.h>
#include<stdlib.h>
#define N 5

int check_id(char *str); 

int main()
{
    char *pid[N] = {"31010120000721656X",
                    "330106199609203301",
                    "53010220051126571",
                    "510104199211197977",
                    "53010220051126133Y"};
    int i;

    for (i = 0; i < N; ++i)
        if (check_id(pid[i])) 
            printf("%s\tTrue\n", pid[i]);
        else
            printf("%s\tFalse\n", pid[i]);
    system("pause");

    return 0;
}


int check_id(char *str)
{ char *p=str;
    while((*p >= '0' && *p <= '9')||*p=='X')
            p++;
 
    if(*p == '\0' && strlen(str) == 18)
        return 1;
    else
        return 0;
 }

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task8

编程代码

#include <stdio.h>
#define N 80
#include<stdlib.h>
void encoder(char *s); 
void decoder(char *s); 

int main()
{
    char words[N];

    printf("输入英文文本: ");
    gets(words);

    printf("编码后的英文文本: ");
    encoder(words); 
    printf("%s\n", words);

    printf("对编码后的英文文本解码: ");
    decoder(words); 
    printf("%s\n", words);
    system("pause");

    return 0;
}


void encoder(char *s)
{int i;
 for(i=0;*(s+i)!=0;i++)
 {if((*(s+i)>=65&&*(s+i)<90)||(*(s+i)>=97&&*(s+i)<122))
 {*(s+i)+=1;continue;}
  if(*(s+i)==90) {*(s+i)=65;continue;}
  if(*(s+i)==122) {*(s+i)=97;continue;}
 } 
    
}


void decoder(char *s)
{int i;
 for(i=0;*(s+i)!=0;i++)
 {if(*(s+i)>65&&*(s+i)<=90)
  {*(s+i)-=1;continue;}
  if(*(s+i)>97&&*(s+i)<=122)
  {*(s+i)-=1;continue;}
  if(*(s+i)==65) {*(s+i)=90;continue;}
   if(*(s+i)==97) 
   {*(s+i)=122;continue;}
 } 
    
}

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posted @ 2023-05-10 20:25  无良无常  阅读(2)  评论(0编辑  收藏  举报