任务一

print(sum)
sum=42
print(sum)

def inc(n):
    sum=n+1
    print(sum)
    return sum

sum=inc(7) +inc(7)
print(sum)

 

 不同,sum1:内置函数,2:变量名,3:定义新函数,4:函数值

任务二

def func1(a, b, c, d, e, f):
    '''返回参数a,b,c,d,e,f构成的列表默认,参数按位置传递; 也支持关键字传递    '''
    return [a,b,c,d,e,f]

def func2(a, b, c,*, d, e, f):
    '''返回参数a,b,c,d,e,f构成的列表    *后面的参数只能按关键字传递    '''
    return [a,b,c,d,e,f]

def func3(a, b, c, /, d, e, f):
    '''返回参数a,b,c,d,e,f构成的列表    /前面的参数只能按位置传递    '''
    return [a,b,c,d,e,f]

# func1调用:按位置传递、按参数传递都可以
print( func1(1,9,2,0,5,3) )
print( func1(a=1, b=9, c=2, d=0, e=5, f=3) )
print( func1(1,9,2, f=3, d=0, e=5))

# func2调用:d,e,f必须按关键字传递
print( func2(11, 99, 22, d=0, e=55, f=33) )
print( func2(a=11, b=99, c=22, d=0, e=55, f=33) )

# func3调用:a,b,c必须按位置传递
print( func3(111, 999, 222, 0, 555, 333))
print( func3(111, 999, 222, d=0, e=555, f=333) )

list1= [1, 9, 8, 4]
print( sorted(list1) )
print( sorted(list1, reverse=True) )
print( sorted(list1) )

 

 python内置函数sorted()中,参数reverse的传递方式是否必须使用关键字传递?

不一定必须使用关键字传递。

def func(a, b, c, /, *, d, e, f):
    return( [a,b,c,d,e,f] )
# 补足一行代码,调用func()并打印生成的列表,使得结果为[1,2,3,4,5,6]
print(func1(a=1, b=2, c=3, d=4, e=5, f=6))

任务三

def solve(a, b, c):
    '''
    求解一元二次方程, 返回方程的两个根
    :para: a,b,c: int 方程系数
    :return: tuple
    '''
    delta = b*b - 4*a*c
    delta_sqrt = abs(delta)**0.5
    p1 = -b/2/a;
    p2 = delta_sqrt/2/a
    if delta>=0:
        root1 = p1 + p2
        root2 = p1 - p2
    else:
        root1 = complex(p1, p2)
        root2 = complex(p1, -p2)
    return root1, root2
print(solve.__doc__)
while True:
    try:
        a,b,c = eval(input('Enter eqution coefficient: '))
        if a == 0:
            raise
    except:
        print('invalid input, or, a is zero')
        break
    else:
        root1, root2 = solve(a, b, c)
        print(f'root1 = {root1:.2f}, root2 = {root2:.2f}')
        print()

 

 

 

 

 

 观察函数solve()的说明信息,打印出来了。

任务四

 

def list_generator(begin,end,step=1):
    list=[]
    while begin<=end:
        list.append(begin)
        begin=begin+step
    return list


list1 = list_generator(-5, 5)
print(list1)
list2 = list_generator(-5, 5, 2)
print(list2)
list3 = list_generator(1, 5, 0.5)
print(list3)

 

 任务六

def encoder(n):
    list1 = []
    for i in n:
        x = ord(i)
        if 65 <= x <= 90 or 97 <= x <= 122:
            if 65 <= x + 5 <= 90 or 97 <= x + 5 <= 122:
                y = chr(x + 5)
                list1.append(y)
            else:
                y = chr(x - 21)
                list1.append(y)
        else:
            list1.append(i)
    z = "".join(list1)
    return z

def decoder(n):
    list1 = []
    for i in n:
        x = ord(i)
        if 65 <= x <= 90 or 97 <= x <= 122:
            if 65 <= x - 5 <= 90 or 97 <= x - 5 <= 122:
                y = chr(x - 5)
                list1.append(y)
            else:
                y=chr(90-(65-(x-5))+1)
                list1.append(y)
        else:
            list1.append(i)
    z = "".join(list1)
    return z

n = input('输入英文文本:')
x1 = encoder(n)
x2 = decoder(x1)
print(f'编码后的文本:{x1}')
print(f'解码后的文本:{x2}')

 

posted on 2022-05-11 15:24  清橙往忆  阅读(9)  评论(3编辑  收藏  举报