java第六次作业
1.使用for循环计算1-100的和,除了以3结尾的那些数
package DaySeven;
public class Test1 {
public static void main(String[] args) {
int sum = 0;
for (int i = 0; i < 100; i++) {
int ge = i % 10;
if (ge != 3) {
sum += i;
}
}
System.out.println(sum);
}
}

2.使用二重循环输出以下图形
*
***
*****
*******
*****
****
***
**
*
package DaySeven;
public class Test2 {
public static void main(String[] args) {
for (int i = 0; i <= 7; i=i+2) {
for (int k = 0; k<=(7-i)/2; k++) {
System.out.print(" ");
}
for (int j = 0; j <=i; j++) {
System.out.print("*");
}
System.out.println();
}
}
}

package DaySeven;
public class Test3 {
public static void main(String[] args) {
for (int i = 6; i >0; i--) {
for (int j = i; j >0; j--) {
System.out.print("*");
}
System.out.println();
}
}
}

3.循环输入学生姓名,直到输入‘Q’程序结束。
package DaySeven;
import java.util.Scanner;
public class Test4 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (true) {
System.out.println("输入学生姓名");
String name = sc.next();
System.out.println(name);
if (name.equals("Q"))
break;
}
}
}

4.输入5个学生成绩,求和,当输入不合法的时候,提示输入错误重新输入。
package DaySeven;
import java.util.Scanner;
public class Test5 {
public static void main(String[] args) {
System.out.println("输入学生成绩");
double sum = 0;
Scanner sc = new Scanner(System.in);
for (int i = 0; i < 5; i++) {
double score = sc.nextDouble();
if (score < 0 || score > 100) {
System.out.println("输入的成绩不合法重新输入");
double score1 = sc.nextDouble();
score = score1;
}
sum = sum+score;
}
System.out.println(sum);
}
}

5.计算 1+ 1/(1+2)+ 1/(1+2+3)+ 1/(1+2+3+4) +…………+1/(1+2+....+10)
package DaySeven;
public class Test6 {
public static void main(String[] args) {
double sum = 0.0;
int sum1 = 0;
for (int i = 1; i <=10; i++) {
sum1 +=i;
sum += 1.0/sum1;
}
System.out.println(sum);
}
}

作业
1.产生一个1-99的随机数,猜数字,若大了就提示“大了点”,若小了就提示“小了点”直到猜对为止。
(判断猜的次数,如果1-3次,提示太棒了 如果5-8次 一般般 如果8次以上 太笨了)
package homework;
import java.util.Random;
import java.util.Scanner;
public class test27 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
Random r = new Random();
int num = r.nextInt(100) + 1;
int count = 0;
for (int i = 1; i <= 100; i++) {
System.out.println("输入你想的数字");
int a = sc.nextInt();
if (a > num) {
System.out.println("大了点");
} else if (a < num) {
System.out.println("小了点");
} else {
System.out.println("幸运数字:" + num);
System.out.println("猜对了");
break;
}
count += 1;
}
System.out.println("累计次数" + count);
if (count>= 1 && count <= 3) {
System.out.println("太棒了");
} else if (count > 3 && count <= 8) {
System.out.println("一般般");
} else if (count > 8) {
System.out.println("太笨了");
}
}
}

2.输入一个数,判断是不是质数(只能被1和自身整除的数是质数)
package homework;
import java.util.Scanner;
public class tets28 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.println("输入一个数");
int a = sc.nextInt();
int b;
boolean zhishu = true;
for (b = 2; b < a - 1; b++) {
if (a % b == 0) {
zhishu = false;
break;
}
}
if (zhishu == true) {
System.out.println("是质数");
} else {
System.out.println("不是质数");
}
}
}

3.求裴波那契数列的第20项是什么。裴波那契数列,1,1,2,3,5,8,13,21……
package homework;
public class test29 {
public static void main(String[] args) {
int a = 1;
int b = 1;
int c = 0;
for (int i = 3; i < 21; i++) {
c = a + b;
a = b;
b = c;
}
System.out.println("第20项:" + c);
}
}

posted on 2021-04-12 21:08 chenyulin11 阅读(26) 评论(0) 收藏 举报
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