摘要:
方法一: int mySqrt(int x) { if(x == 0) { return 0; } int ans = exp(0.5*log(x)); int k = ans+1; //int r = k*k; if((long long) k*k <=x) { return k; } else 阅读全文
posted @ 2020-05-09 22:28
HappyCoder_1
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摘要:
vs里: std::string stdf = "usr=\"abcd\" "; 阅读全文
posted @ 2020-05-09 11:17
HappyCoder_1
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