摘要: if($_POST){ $title=$_POST['title']; $descs=$_POST['descs']; $content=$_POST['content']; $uname=$_POST['img']; $conn=new mysqli('localhost','root','roo 阅读全文
posted @ 2020-06-08 21:32 丶玲珑骰子安红豆 阅读(100) 评论(0) 推荐(0)