05 2017 档案

最小公倍数hdu1108
摘要：1 #include 2 #include 3 #include 4 using namespace std; 5 int gcd(int a,int b) 6 { 7 return b==0?a:gcd(b,a%b); 8 } 9 int main() 10 { 11 int b,a; 12 while(~scanf("%d%d",&a,&b))... 阅读全文
posted @ 2017-05-30 22:53 TTTCoder 阅读(226) 评论(0) 推荐(0)
hdu1098费马小定理
摘要：Ignatius's puzzle Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9783 Accepted Submission(s): 68 阅读全文
posted @ 2017-05-30 22:28 TTTCoder 阅读(349) 评论(0) 推荐(0)
hdu1005
摘要：Number Sequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 171693 Accepted Submission(s): 42 阅读全文
posted @ 2017-05-17 22:42 TTTCoder 阅读(269) 评论(0) 推荐(0)
hdu1003最大连续子序列
摘要：Problem Description Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7 阅读全文
posted @ 2017-05-16 23:31 TTTCoder 阅读(252) 评论(0) 推荐(0)
hdu5974
摘要：A Simple Math Problem Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1795 Accepted Submission(s) 阅读全文
posted @ 2017-05-14 23:52 TTTCoder 阅读(276) 评论(0) 推荐(0)
HDU5980
摘要：As is known to all,the ASCII of character 'a' is 97. Now,find out how many character 'a' in a group of given numbers. Please note that the numbers her 阅读全文
posted @ 2017-05-13 21:44 TTTCoder 阅读(254) 评论(0) 推荐(0)
hdu1133
摘要：Buy the Ticket Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6867 Accepted Submission(s): 2845 阅读全文
posted @ 2017-05-13 00:53 TTTCoder 阅读(340) 评论(0) 推荐(0)
CF754A
摘要：One spring day on his way to university Lesha found an array A. Lesha likes to split arrays into several parts. This time Lesha decided to split the a 阅读全文
posted @ 2017-05-11 21:41 TTTCoder 阅读(507) 评论(1) 推荐(0)
快速幂模板
摘要：1 int powermod(int a,int b,int c) 2 { 3 int ans=1; 4 a=a%c; 5 while(b>0) 6 { 7 if(b%2==1) 8 ans=(ans*a)%c; 9 b=b/2; 10 a=(a*a)%c; 11 } 12 ... 阅读全文
posted @ 2017-05-04 12:38 TTTCoder 阅读(217) 评论(0) 推荐(0)