本文源于维生素C.net的一篇文章利用数学方法来大大降低一个逻辑判断实现的难度的例子
<script type="text/javascript">
var PasswordStrength =
{
Level : ["高，实在是高","还行啦","靠，这样也行"],
LevelValue : [30,20,0],//强度值
Factor : [1,2,5],//字符加数,分别为字母，数字，其它
KindFactor : [0,0,10,20],//密码含几种组成的加数
Regex : [/[a-zA-Z]/g,/\d/g,/[^a-zA-Z0-9]/g] //字符正则数字正则其它正则
}
PasswordStrength.StrengthValue = function(pwd)
{
var strengthValue = 0;
var ComposedKind = 0;
for(var i = 0 ; i < this.Regex.length;i++)
{
var chars = pwd.match(this.Regex[i]);
if(chars != null)
{
strengthValue += chars.length * this.Factor[i];
ComposedKind ++;
}
}
strengthValue += this.KindFactor[ComposedKind];
return strengthValue;
}
PasswordStrength.StrengthLevel = function(pwd)
{
var value = this.StrengthValue(pwd);
for(var i = 0 ; i < this.LevelValue.length ; i ++)
{
if(value >= this.LevelValue[i] )
return this.Level[i];
}
}
alert(PasswordStrength.StrengthLevel("23"));
alert(PasswordStrength.StrengthLevel("abcd123"));
alert(PasswordStrength.StrengthLevel("abcd!%23"));
</script>
posted @ 2006-05-14 11:07
Lyn 阅读(3369)
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DHTML & Javascript