mysql 经纬度范围查询排序优化

      var req = new
            {
                //经度
                Longitude = 1,
                //纬度
                Latitude = 1,
                //跳过条数
                offset = 1,
                //显示条数
                limit = 1,
                //条件范围  每增加1搜索范围差不多增加110km
                scope = 10,
            };
            
            string sql = $@"select * from store where 1=1 ";
            sql = sql + $@"and longitude > ({req.Longitude}-{ req.scope}) 
                                and longitude < ({req.Longitude}+{ req.scope})
                                and latitude > ({req.Latitude}-{ req.scope})
                                and latitude< ({req.Latitude}+{ req.scope})
                                order by ACOS(SIN(({req.Latitude} * 3.1415) / 180 ) *SIN((latitude * 3.1415) / 180 ) +COS(({req.Latitude} * 3.1415) / 180 ) * 
                                COS((latitude * 3.1415) / 180 ) *COS(({req.Longitude}* 3.1415) / 180 - (longitude * 3.1415) / 180 ) ) * 6380 ";
            sql = sql + ($@" limit { req.offset},{ req.limit}");

 

posted @ 2019-08-13 09:11  庸人l自扰  阅读(638)  评论(0编辑  收藏  举报