利用WebClient上传参数及文件流到远程ashx服务

1 思路:

WebClient.UploadFile()方法可以上传文件;UploadData()方法可以上传数据参数;如何合二为一既上传文件又上传参数呢?可将文件也当做参数,调用UploadData()方法

2  客户端


 1 FileStream fs = new FileStream(“需上传文文件路径”, FileMode.Open, FileAccess.Read);
 2 
 3             byte[] byteFile = new byte[fs.Length];
 4 
 5             fs.Read(byteFile, 0, Convert.ToInt32(fs.Length));
 6 
 7             fs.Close();
 8 
 9             string postData = "param1=pwd&FileName=file1.xml&UploadFile=" + HttpUtility.UrlEncode(Convert.ToBase64String(byteFile));
10 
11             var webclient = new WebClient();
12 
13             webclient.Headers.Add("Content-Type", "application/x-www-form-urlencoded");
14 
15             byte[] byteArray = Encoding.UTF8.GetBytes(postData);
16 
17             byte[] buffer = webclient.UploadData(“远程ashx URL”, "POST", byteArray);
18 
19             var msg = Encoding.UTF8.GetString(buffer);

 

3   服务端

 

1 string param1= context.Request["param1"].ToString();
2   FileStream fs = new FileStream(“需要保存文件的路径”, FileMode.Create, FileAccess.Write);
3         fs.Write(Convert.FromBase64String(context.Request["UploadFile"].ToString()), 0, Convert.FromBase64String(context.Request["UploadFile"].ToString()).Length);
4         fs.Flush();
5         fs.Close();

 


 

posted @ 2013-03-04 16:46    阅读(7734)  评论(1编辑  收藏  举报