输入一串字符,算出各种字符的个数--简单

源程序:

import java.util.Scanner;

public class p78_10 {

  public static void main(String[] args)

  {

    int n_char=0,n_digit=0,n_other=0;

    char []a=new char[100];

    Scanner reader=new Scanner(System.in);

    System.out.print("请输入一串字符(包含字母、数字和特殊字符):");

    String str1=reader.next();

    for(int i=0;i<str1.length();i++)

    {

      a[i]=str1.charAt(i);

      if(a[i]>='a'&&a[i]<='z' || a[i]>='A'&&a[i]<='Z')

        n_char++;

      else if(a[i]>='0'&&a[i]<='9')

        n_digit++;

      else

        n_other++; 

    }

    System.out.println("字母的个数:"+n_char+" ");

    System.out.println("数字的个数:"+n_digit+" ");

    System.out.println("特殊字符的字母的个数:"+n_other+" ");

    System.out.println("全部字符个数:"+str1.length()+" ");

    reader.close();

  } 

}

 

 运行结果:

 

posted @ 2019-07-04 14:02  bobo哥  阅读(2208)  评论(0编辑  收藏  举报