C++构造函数按下列顺序被调用:
(1)任何虚拟基类的构造函数按照它们被继承的顺序构造;
(2)任何非虚拟基类的构造函数按照它们被继承的顺序构造;
(3)任何成员对象的构造函数按照它们声明的顺序调用;
(4)类自己的构造函数。

#include <iostream>

using namespace std;

class OBJ1
{
public:
    OBJ1(){ cout <<"OBJ1\n"; }
};

class OBJ2
{
public:
    OBJ2(){ cout <<"OBJ2\n"; }
};

class Base1
{
public:
    Base1(){ cout <<"Base1\n"; }
};

class Base2
{
public:
    Base2(){ cout <<"Base2\n"; }
};

class Base3
{
public:
    Base3(){ cout <<"Base3\n"; }
};

class Base4
{
public:
    Base4(){ cout <<"Base4\n"; }
};

class Derived :public Base1, virtual public Base2,
    public Base3, virtual public Base4
{
public:
    Derived() :Base4(), Base3(), Base2(),
        Base1(), obj2(), obj1()
    {
        cout <<"Derived ok.\n";
    }
protected:
    OBJ1 obj1;
    OBJ2 obj2;
};

int main()
{
    Derived aa;
    cout <<"This is ok.\n";

    int i;
    cin >> i;

    return 0;
}

结果:

Base2
Base4
Base1
Base3
OBJ1
OBJ2
Derived ok.
This is ok.

posted on 2010-04-16 13:59  cppfans  阅读(8707)  评论(0编辑  收藏  举报