判断身份证:要么是15位,要么是18位,最后一位可以为字母,并写程序提出其中的年月日 (正则表达式)
package com.test; import java.util.regex.Matcher; import java.util.regex.Pattern; public class ID { public static void main(String[] args) { String[] strs = { "130681198712092019", "13068119871209201x", "13068119871209201", "123456789012345", "12345678901234x", "1234567890123" }; Pattern p1 = Pattern.compile("(\\d{17}[0-9a-zA-Z]|\\d{14}[0-9a-zA-Z])"); for (int i = 0; i < strs.length; i++) { Matcher matcher = p1.matcher(strs[i]); System.out.println(strs[i] + ":" + matcher.matches()); } Pattern p2 = Pattern.compile("\\d{6}(\\d{8}).*"); // 用于提取出生日字符串 Pattern p3 = Pattern.compile("(\\d{4})(\\d{2})(\\d{2})");// 用于将生日字符串进行分解为年月日 for (int i = 0; i < strs.length; i++) { Matcher matcher = p2.matcher(strs[i]); boolean b = matcher.find(); if (b) { String s = matcher.group(1); Matcher matcher2 = p3.matcher(s); if (matcher2.find()) { System.out.println( "生日为" + matcher2.group(1) + "年" + matcher2.group(2) + "月" + matcher2.group(3) + "日"); } } } } }