生成简单的Makefile文件(Python实现)

在linux下写几个测试程序，还要一行行的输入g++命令进行编译，当经常改测试代码的时候，那一次次的敲（或者一次次的上线箭头选）也感觉不爽，不如make来的快。用Makefile的好处就不用多说了，这里我写了个脚本，其功能是自动搜索当前目录（不包括子目录）下的“.c”文件生成Makefile文件。
代码在这里，功能有限（适用于单个文件是一个独立的测试代码的情况），需要的朋友可以稍作修改以满足需求。

 1 #! /usr/bin/python
 2 '''
 3  File      : genMakefile.py
 4  Author    : Mike
 5  E-Mail    : Mike_Zhang@live.com
 6 '''
 7 import os
 8 
 9 def genMakefileStr(dir,surfix = '.c'):
10     msg = ''
11     msg = msg + 'CC = gcc' + '\n'
12     msg = msg +  'CFLAGS = -g -O2 -Wall' + '\n\n'
13     
14     fList = []
15     for dirPath,dirNames,fileNames in os.walk(dir):
16         for file in fileNames:
17             name,extension = os.path.splitext(file)
18             if extension == surfix:
19                 fList.append(name)
20         break # only search the current directory
21     str1 = 'all:\n'
22     str2 = ''
23     str3 = 'clean:\n'
24     for f in fList:
25         str1 = str1 + '\tmake ' + f + '\n'
26         str2 = ('%s%s:%s.o\n') % (str2,f,f)
27         str2 = ('%s\t$(CC) -o %s %s.o\n\n') % (str2,f,f)
28         str3 = ('%s\trm -f %s\n') % (str3,f)
29     str3 = str3 + '\trm -f *.o\n'
30     strClean = '.c.o:\n\t$(CC) $(CFLAGS) -c -o $*.o $<\n'
31     msg = ('%s%s\n%s\n%s\n%s') % (msg,str1,str2,str3,strClean) 
32     #print 'msg : \n'
33     #print msg
34     return msg
35 
36 if __name__ == '__main__':
37     str = genMakefileStr('.','.c')
38     file = open("Makefile","w")
39     file.write(str)
40     file.close()
41     print str

运行效果如下（示例）：

 1 # ./genMakefile.py          
 2 CC = gcc
 3 CFLAGS = -g -O2 -Wall
 4 
 5 all:
 6         make pfun1
 7         make pfun2
 8 
 9 pfun1:pfun1.o
10         $(CC) -o pfun1 pfun1.o
11 
12 pfun2:pfun2.o
13         $(CC) -o pfun2 pfun2.o
14 
15 
16 clean:
17         rm -f pfun1
18         rm -f pfun2
19         rm -f *.o
20 
21 .c.o:
22         $(CC) $(CFLAGS) -c -o $*.o $<

运行脚本后进行make即可。

附：

感觉上面的那个脚本用着不方便，随后修改修改，代码如下：

#! /usr/bin/python
'''
  File      : genMakefile.py
  Author    : Mike
  E-Mail    : Mike_Zhang@live.com
'''
import os,sys
 
surfix = ['.c','.cpp']

def genMakefileStr(dir):
    msg = ''
    msg = msg + 'CC = g++ ' + '\n'
    msg = msg +  'CFLAGS = -g -O2 -Wall' + '\n\n'
    
    fList = []
    for dirPath,dirNames,fileNames in os.walk(dir):
        for file in fileNames:
            name,extension = os.path.splitext(file)
            if surfix.count(extension) > 0:
                fList.append(name)
        break # only search the current directory
    str1 = 'all:\n'
    str2 = ''
    str3 = 'clean:\n'
    for f in fList:
        str1 = str1 + '\tmake ' + f + '\n'
        str2 = ('%s%s:%s.o\n') % (str2,f,f)
        str2 = ('%s\t$(CC) -o %s %s.o\n\n') % (str2,f,f)
        str3 = ('%s\trm -f %s\n') % (str3,f)
    str3 = str3 + '\trm -f *.o\n'
    strClean = '.c.cpp.o:\n\t$(CC) $(CFLAGS) -c -o $*.o $<\n'
    msg = ('%s%s\n%s\n%s\n%s') % (msg,str1,str2,str3,strClean) 
    #print 'msg : \n'
    #print msg
    return msg
 
if __name__ == '__main__':
    for arg in sys.argv[1:]:
        print arg
    str = genMakefileStr(arg)
    if arg[-1] == '/':arg = arg[:-1]
    file = open(arg+"/Makefile","w")
    file.write(str)
    file.close()
    print str

把文件genMakefile.py改名为genMakefile,复制到/usr/local/bin下，以后在需要的目录里面执行如下命令即可：

genMakefile .

本文github地址：

https://github.com/mike-zhang/mikeBlogEssays/blob/master/2011/生成简单的Makefile文件(Python实现).txt

欢迎补充

posted on 2012-01-17 13:53 Mike_Zhang 阅读(6567) 评论(2) 编辑收藏举报