jquery ajax post


                    $.ajax({type:"post",
                    url:"PhotoTransferNew.ashx",
                   data:{
                        username:"000",
                         job:"111"
                    },
                    error:function(msg){
                      alert("error") ;
                    },
                    success:function (msg){
                      alert("success");
                    }
                    });

posted @ 2012-02-09 15:57  郑文亮  阅读(468)  评论(0编辑  收藏  举报