python 二叉树实现带括号的四则运算
摘要：
#!/usr/bin/python #* encoding=utf-8 s = "20-5*(0+1)*5^(6-2^2)" c = 0 top = [0,s[c],0] op = [["0","1","2","3","4","5","6","7","8","9"],["+","-"],["*","/&quo 阅读全文
posted @ 2016-12-13 22:45 空老吹 阅读(1444) 评论(0) 推荐(0) 编辑
