摘要:        
1 class Solution 2 { 3 public: 4 int uniquePaths(int m, int n) 5 { 6 vector<vector<int>> dp(m,vector<int>(n,1)); 7 for(int i = 1;i < m;i ++) 8 { 9 for    阅读全文
posted @ 2020-03-19 19:43
Jinxiaobo0509
阅读(73)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 void spilt(string s,char c,vector<string> &res) 4 { 5 istringstream iss(s); 6 string temp; 7 while(getline(iss,temp,c)) 8 { 9 /    阅读全文
posted @ 2020-03-19 19:20
Jinxiaobo0509
阅读(111)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 //spilt函数的实现 2 //假设以空格切分:char c = ' '; 3 class Solution 4 { 5 vector<string> res; 6 void spilt(string s,char c,vector<string> &res) 7 { 8 istringstr    阅读全文
posted @ 2020-03-19 19:18
Jinxiaobo0509
阅读(172)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 public: 4 vector<vector<int>> merge(vector<vector<int>>& nums) 5 { 6 vector<vector<int>> res; 7 if(nums.empty()) return res; 8     阅读全文
posted @ 2020-03-19 18:39
Jinxiaobo0509
阅读(112)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 public: 4 bool canJump(vector<int>& nums) 5 { 6 int n = nums.size(); 7 int max_size = nums[0]; 8 for(int i = 0;i < n;i ++) 9 {     阅读全文
posted @ 2020-03-19 18:07
Jinxiaobo0509
阅读(97)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 vector<int> ans; 4 public: 5 vector<int> spiralOrder(vector<vector<int>>& matrix) 6 { 7 if(matrix.size() == 0) return {}; 8 int    阅读全文
posted @ 2020-03-19 18:04
Jinxiaobo0509
阅读(105)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 public: 4 int longestCommonSubsequence(string text1, string text2) 5 { 6 int m = text1.size(); 7 int n = text2.size(); 8 vector    阅读全文
posted @ 2020-03-19 16:13
Jinxiaobo0509
阅读(103)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 public: 4 int findNumberOfLIS(vector<int>& nums) 5 { 6 if(nums.size() == 0) return 0; 7 int n = nums.size(); 8 vector<int> dp(n    阅读全文
posted @ 2020-03-19 15:58
Jinxiaobo0509
阅读(129)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 class Solution 2 { 3 public: 4 int lengthOfLIS(vector<int>& nums) 5 { 6 if(nums.size() == 0) return 0; 7 int n = nums.size(); 8 int res = INT_MIN; 9    阅读全文
posted @ 2020-03-19 12:56
Jinxiaobo0509
阅读(103)
评论(0)
推荐(0)
        
            
        
        
摘要:        
1 //看成一个下三角形 2 class Solution 3 { 4 public: 5 int minimumTotal(vector<vector<int>>& triangle) 6 { 7 int n = triangle.size(); 8 int res = INT_MAX; 9 ve    阅读全文
posted @ 2020-03-19 11:39
Jinxiaobo0509
阅读(165)
评论(0)
推荐(0)
        
                    
                
浙公网安备 33010602011771号