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摘要: 1 class Solution 2 { 3 public: 4 int minDistance(string word1, string word2) 5 { 6 int m = word1.size(); 7 int n = word2.size(); 8 9 vector<vector<int 阅读全文
posted @ 2020-04-16 10:36 Jinxiaobo0509 阅读(113) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 public: 4 int rob(vector<int>& nums) 5 { 6 if(nums.size() == 0) return 0; 7 if(nums.size() == 1) return nums[0]; 8 if(nums.size 阅读全文
posted @ 2020-04-16 10:14 Jinxiaobo0509 阅读(104) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 public: 4 // 前i个字符串构成 == 前i-1个字符串构成(只有一个字符1-9) 5 // +前i-2个字符串构成(只有两个字符10-26) 6 int numDecodings(string s) 7 { 8 int n = s.size( 阅读全文
posted @ 2020-04-16 09:58 Jinxiaobo0509 阅读(181) 评论(0) 推荐(0)
摘要: 1 // 统计个数,相同位置相同数字的个数 >A的个数 2 // 不同位置相同数字的个数 >B的个数 3 class Solution 4 { 5 public: 6 string getHint(string secret, string guess) 7 { 8 int n = secret.s 阅读全文
posted @ 2020-04-15 16:38 Jinxiaobo0509 阅读(118) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 public: 4 bool canWinNim(int n) 5 { 6 //如果不是4的倍数,必赢 7 //如果是4的倍数,必输 8 return n % 4 != 0; 9 } 10 }; 阅读全文
posted @ 2020-04-15 15:29 Jinxiaobo0509 阅读(87) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 vector<string> res; 4 void spilt(string s,char c,vector<string> &res) 5 { 6 istringstream iss(s); 7 string temp; 8 while(getlin 阅读全文
posted @ 2020-04-15 15:09 Jinxiaobo0509 阅读(117) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 int dx[8] = {1,1,0,-1,-1,-1,0,1}; 4 int dy[8] = {0,1,1,1,0,-1,-1,-1}; 5 public: 6 void gameOfLife(vector<vector<int>>& board) 7 阅读全文
posted @ 2020-04-15 14:40 Jinxiaobo0509 阅读(119) 评论(0) 推荐(0)
摘要: 1 /* 2 * Below is the interface for Iterator, which is already defined for you. 3 * **DO NOT** modify the interface for Iterator. 4 * 5 * class Iterat 阅读全文
posted @ 2020-04-15 13:57 Jinxiaobo0509 阅读(96) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 public: 4 void moveZeroes(vector<int>& nums) 5 { 6 int n = nums.size(); 7 int begin = 0; 8 for(int i = 0;i < n;i ++) 9 { 10 if( 阅读全文
posted @ 2020-04-15 12:44 Jinxiaobo0509 阅读(84) 评论(0) 推荐(0)
摘要: 1 class Solution 2 { 3 public: 4 int numSquares(int n) 5 { 6 queue<pair<int,int>> Q; 7 Q.push(make_pair(n,0)); 8 vector<bool> visit(n+1,false); 9 //层序 阅读全文
posted @ 2020-04-15 11:41 Jinxiaobo0509 阅读(138) 评论(0) 推荐(0)
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