博客搬家了,欢迎大家关注,https://bobjin.com1、原生ajax请求方式: 1 var xhr = new XMLHttpRequest(); 2 xhr.open("POST", "http://xxxx.com/demo/b/index.php", true); 3 xhr.wit Read More
posted @ 2017-04-17 10:58 猿客 Views(6518) Comments(0) Diggs(0) Edit