C#+AE 对于做属性查询的一定总结

本人刚做了有关属性查询的一些功能的实现,在这总结一下。

有错误之处和不专业之处还希望GIS和AE开发的高手们给以指点。

 

//******其中第二部分发生了点错误,现在已更改***********//

 

①:据FeatureLayer得到Feature的方法:

代码如下:

                ILayer pLayer;
                pLayer = frm1.axMapControl1.Map.get_Layer(LayerBoxEdit.SelectedIndex) as ILayer;//frm1和LayerBoxEdit.SelectedIndex都是变量
                IFeatureLayer pFeatureLayer;
                pFeatureLayer = pLayer as IFeatureLayer;
                if (pFeatureLayer == null)
                {
                    return;
                }

               
              
                IFeatureCursor pFeatureCursor;
                pFeatureCursor = pFeatureLayer.Search(null, false);
                IFeature pFeature;
                pFeature = pFeatureCursor.NextFeature();

②:据FeatureClass得到Feature的方法:

            

 IFeatureLayer pFeatureLayer;
                pFeatureLayer = frm1.axMapControl1.Map.get_Layer(0) as IFeatureLayer;
                IFeatureClass pFeatureClass;
                pFeatureClass = pFeatureLayer.FeatureClass;
                IQueryFilter pQueryFilter;
                pQueryFilter = new QueryFilterClass();
              //  pQueryFilter.WhereClause = "";

                IFeature pFeature;

         for(int j=0;j< pFeatureClass.FeatureCount(pQueryFilter); j++)

            {

                 pFeature = pFeatureClass.GetFeature(j);
            }

              ③:在TreeList中点击子节点得到Feature的方法:

                      

  if (e.Node.HasChildren)
                {
                    return;
                }

if (!(e.Node.HasChildren)) //***********//这个存在bug,若节点超过两级则出错
                {

             

 for (int i = 0; i < this.axMapControl1.LayerCount; i++)
                    {

                        //如果父节点名称和图层名相同,获取索引
                        if (e.Node.ParentNode.GetValue(0).ToString() == this.axMapControl1.get_Layer(i).Name)
                        {
                            layerIndex = i;
                            IFeature pFeature;                             
 
                           pFeature = (this.axMapControl1.get_Layer(layerIndex) as IFeatureLayer).FeatureClass.GetFeature(int.Parse(this.treeList1.FocusedNode.GetValue(0).ToString())); ;

                         }

                     }

 

posted @ 2012-09-28 11:02  南方以南  阅读(3869)  评论(0编辑  收藏  举报