摘要：bool judge(Point &a,Point &b,Point &c,Point &d){//判断两线段是否相交 //快速排斥: //以两线段为对角线的矩形如果没有重叠部分，两线段则必不可能相交 if(!(min(a.x,b.x)<=max(c.x,d.x)&&min(c.x,d.x)<=ma 阅读全文