编程之美---求数组中最长递增子序列LIS

对于那个O(nlgn)的算法实在用的不熟,大概能理解,不过还是欠火候,在此不贴了,以后再重新编辑

 

#include<stdio.h>
#include<stdlib.h>
#include<cstring>
#include<assert.h>

int LIS(int *a, int n)
{
	assert(NULL != a);
	int *dp = new int[n];
	memset(dp, 0, sizeof(dp));
	for(int i=0; i<n; i++)
	{
		dp[i] = 1;
		for(int j=0; j<i; j++)
		{
			if(a[i] > a[j] && (dp[j]+1>dp[i]))
				dp[i] = dp[j] + 1;
		}
	}
	int ret = dp[n-1];
	delete []dp;
	return ret;
}

void test()
{
	int n = 0;
	while(scanf("%d", &n)!=EOF)
	{
		if(n == 0) break;
		int *a = new int[n];
		for(int i=0; i<n; i++)
			scanf("%d", &a[i]);
		int ret = LIS(a, n);
		printf("%d\n", ret);
		delete []a;
	}
}

int main()
{
	test();
	return 0;
}


 

 

posted @ 2013-04-11 11:25  xinyuyuanm  阅读(229)  评论(0编辑  收藏  举报