Everything negative - pressure, challenges - is all an opportunity for me to rise.

题目要去掉一些的a[i],b[i]对，使得sigma(a[i])/sigma(b[i])最大，设100*sigma(a[i])/sigma(b[i])=r 最大，则100*sigma(a[i])-sigma(b[i])*r=0时r最大。因为这个式子是单调的，所以二分枚举答案，sigma(100*ai-mid*bi)==0时就为答案View Code #include<cstdio>#include<cstring>#include<cmath>#include<algorithm>using namespace std;struct node{ Read More