12 2021 档案

INT_MIN绝对值
摘要：求某个int32的绝对值： unsigned int abs_n = n < 0 ? UINT_MAX - ((unsigned int)(n)) + 1U : (unsigned int)(n); Update: As @aka.nice suggests, we can actually rep 阅读全文

posted @ 2021-12-20 21:17 wsw_seu 阅读(47) 评论(0) 推荐(0)

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