摘要:
#includeint main(void){ int m,n; float result,sum; float fact(int n); printf("enter m and n:"); scanf("%d %d",&m,&n); sum=fact(m-n); result=fact(m)/(fact(n)*sum); printf("result=%.0f\n",result); return 0;}float fact(int n){ int i; float result; result=1; for(i=. 阅读全文
posted @ 2013-10-21 19:23
红颜文丛
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摘要:
#includedouble fact(int i);int main(void){ int i; double sum; sum=0; for(i=1;i<=100;i++) sum=sum+fact(i); printf("1!+2!+……+100!=%e\n",sum); return 0;}double fact(int n){ int i; double product; product=1; for(i=1;i<=n;i++) product=product*i; retur... 阅读全文
posted @ 2013-10-21 09:27
红颜文丛
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