摘要:
方法1:select min(c) from (select min(b) as c from tab_nameunionselect min(a) as c from tab_name);方法2:select least(min(A),min(B)) from table;least(...),greatest(...)中如果含有null的话,无法得到结果select greatest(max(A),max(B)) from table; 阅读全文
posted @ 2013-01-10 00:17
horizon~~~
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