摘要： 题目链接。分析：数论了解的还不算太多，解的时候，碰到了不小的麻烦。设答案为x，n = (1#include #include #include #include #include #include #include #include #include using namespace std;typedef long long LL;void gcd(LL a, LL b, LL &d, LL &x, LL &y) { if(!b) { d = a; x = 1; y = 0; } else { gcd(b, a%b, d, y, x); y-= x*(a/b); }}i 阅读全文