dij+heap

学了一下dij+heap

用它做了做HDU2544

遇到了两个问题:

1.堆数组H开的太小会RE

2.对于该题跑时15ms, 不加优化15ms,spfa跑时0ms

探究:

1.对于第一个问题:结点是会被重复加入的。因为每次松弛时,都会有结点加入堆,因此加入堆的结点总数会大于总的结点数。

2.对于第二个问题,在网上找了找资料,迷茫中闪现一丝曙光。资料地址:http://blog.csdn.net/lyso1/article/details/5687180

 

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

#define MAXN 106
#define INF (1<<20)

int d[MAXN], w[MAXN][MAXN];
unsigned char vis[MAXN];

int cmp(int i, int j){
    return d[i]>d[j];
}

void swap(int A[], int i, int j){
    int t = A[i];
    A[i] = A[j];
    A[j] = t;
}

void Heap_init(int A[]){
    A[0] = 0;
}

int heap_empty(int A[]){
    return A[0] == 0;
}

void heap_insert(int A[], int x){
    int i = ++A[0];
    A[A[0]] = x;

    while(i != 1){
        if(!cmp(A[i], A[i/2])) swap(A, i, i/2);
        else break;

        i /= 2;
    }
}

int delete_min(int A[]){
    int x = A[1], y = A[A[0]], i = 1;
    A[0]--;
    if(A[0] >= 1){
        A[1] = y;
        while((i*=2) <= A[0]){
            if(i+1<=A[0] && !cmp(A[i+1],A[i])) i++;

            if(cmp(A[i/2], A[i])) swap(A, i/2, i);
            else break;
        }
    }
    return x;
}

void Dijkstra(int v0, int n){
    int H[2000], i, y;
    Heap_init(H);

    for(i=0; i<n; i++){d[i] = INF; vis[i] = 0;}

    d[v0]=0;
    heap_insert(H, v0);

    while(!heap_empty(H)){
        int x;
        x = delete_min(H);
        if(!vis[x]){
            vis[x] = 1;
            for(y=0; y<n; y++){
                if(d[y] > d[x] + w[x][y]){
                    d[y] = d[x] + w[x][y];
                    heap_insert(H, y);
                }
            }
        }
     }
 }

int main(){
    int n, m, a, b, c, i, j;

    while(scanf("%d %d", &n, &m) == 2 && (n != 0 || m != 0)){
        for(i=0; i<n; i++){
            for(j=0; j<n; j++)
                w[i][j] = INF;
        }
        for(i=0; i<m; i++){
            scanf("%d %d %d", &a, &b, &c);
            w[a-1][b-1] = w[b-1][a-1] = c;
        }

        Dijkstra(0, n);
        printf("%d\n", d[n-1]);
    }
    return 0;
}

 

posted on 2013-03-12 15:21  Still_Raining  阅读(789)  评论(0编辑  收藏  举报