摘要:
注意一点:n为负数时, n = -n; 有可能会溢出,当n == INT_MIN时 double pow(double x, int n) { // Note: The Solution object is instantiated only once and is reused by each test case. if(equal(x,0.0)&&n>1); if((n&0x1)==0) return res*res; else return res*res*x; } ... 阅读全文
posted @ 2013-10-18 14:59
summer_zhou
阅读(176)
评论(0)
推荐(0)
浙公网安备 33010602011771号