摘要: double helper(double x, unsigned int n) { if(n==1) return x; double result; if(n%2==0) { result = helper(x,n/2); return result*result; }else{ result = helper(x,(n-1)/2); return result*result*x; } ... 阅读全文
posted @ 2013-05-26 17:17 summer_zhou 阅读(137) 评论(0) 推荐(0)