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Let the Balloon RiseTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 57595Accepted Submission(s): 21046Problem DescriptionContest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time 阅读全文
posted @ 2013-07-27 14:46
守护生命的绿荷
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又一版 A+BTime Limit: 2000/1000 MS (Java/Others)Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11438Accepted Submission(s): 4273Problem Description输入两个不超过整型定义的非负10进制整数A和B(int main(){ int a,b,m,n,i,s[100000]; while(scanf("%d",&m)&&m!=0) { scanf("%d%d",& 阅读全文
posted @ 2013-07-27 13:23
守护生命的绿荷
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平方和与立方和Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 69866Accepted Submission(s): 21734Problem Description给定一段连续的整数,求出他们中所有偶数的平方和以及所有奇数的立方和。Input输入数据包含多组测试实例,每组测试实例包含一行,由两个整数m和n组成。Output对于每组输入数据,输出一行,应包括两个整数x和y,分别表示该段连续的整数中所有偶数的平方和以及所有奇数的立方和。你可以认 阅读全文
posted @ 2013-07-27 13:20
守护生命的绿荷
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成绩转换Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 57338Accepted Submission(s): 24955Problem Description输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下:90~100为A;80~89为B;70~79为C;60~69为D;0~59为E;Input输入数据有多组,每组占一行,由一个整数组成。Output对于每组输入数据,输出一行。如果输入数据不在0~100范围内,请输出一行:“ 阅读全文
posted @ 2013-07-27 13:17
守护生命的绿荷
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