DSH2WRT

摘要： 题目地址：http://pat.zju.edu.cn/contests/pat-b-practise/1002 1 #include<iostream> 2 #include<string> 3 4 //数字从高位到低位输出的例子——本题思想，申请足够打的空间 5 using namespace std; 6 7 string pingyin[10] = {"ling", "yi", "er", "san", "si", "wu", "liu 阅读全文

摘要： 1 #include<stdio.h> 2 3 int main() 4 { 5 int n; 6 int step = 0; 7 scanf("%d", &n); 8 while( 1 != n ) 9 {10 if( (n%2) == 0 )11 {12 n = n / 2; 13 ++step;14 } 15 else16 {17 n = 3 * n + 1;18 ... 阅读全文